Java：当单词之间的空格数量可变时，用空格拆分字符串？
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原文地址: http://stackoverflow.com/questions/19019560/
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Java: Splitting a string by whitespace when there is a variable number of whitespaces between words?
提问by
I have the following:
我有以下几点：
String string = "1-50 of 500+";
String[] stringArray = string.split(" ");
Printing out all the elements in this array gives me the following:
打印出这个数组中的所有元素给我以下内容：
Element 1: 1-50
Element 2: ?of?500+
How can I get it to split elements by the requirement that there is at least one whitespace between the words?
我怎样才能通过要求单词之间至少有一个空格来拆分元素？
In other words, I want my elements to be:
换句话说，我希望我的元素是：
Element 1: 1-50
Element 2: of
Element 3: 500+
采纳答案by Sri Harsha Chilakapati
Use \\s+to split on spaces even if they are more.
使用\\s+对空间分割，即使他们都多。
String string = "1-50 of 500+";
String[] stringArray = string.split("\s+");
for (String str : stringArray)
{
System.out.println(str);
}
Full example: http://ideone.com/CFVr6N
完整示例：http: //ideone.com/CFVr6N
EDIT:
编辑：
If you also want to split on tabs, change the regex to \\s+|\\t+and it detects both spaces and tabs as well.
如果您还想在制表符上拆分，请将正则表达式更改为\\s+|\\t+，它还会检测空格和制表符。
回答by newuser
String[] stringArray = string.split(" +");
instead of
代替
String[] stringArray = string.split(" ");
回答by Siva
You can split using regex
您可以使用正则表达式拆分
string.split("\s+");
回答by Vimal Bera
Use this to spilt the String.
使用它来溢出字符串。
String[] stringArray = string.split("\s+");
回答by Vicky Thakor
Your Program is correct but you put two space after 1-50. So Its giving you that output. Remove one space and you are done. No need to change the code. But if there is a two space then you should use string.split("\\s+")
您的程序是正确的，但您在1-50. 所以它给你那个输出。删除一个空格，你就完成了。无需更改代码。但是如果有两个空格那么你应该使用string.split("\\s+")
回答by Sri Harsha Chilakapati
With guava Splitter:
番石榴Splitter：
package com.stackoverflow.so19019560;
import com.google.common.base.CharMatcher;
import com.google.common.base.Splitter;
import com.google.common.collect.Lists;
import java.util.List;
public class Foo {
private static final Splitter SPLITTER = Splitter.on(CharMatcher.WHITESPACE).omitEmptyStrings();
public static void main(final String[] args) {
final String string = "1-50 of \t\n500+";
final List<String> elements = Lists.newArrayList(SPLITTER.split(string));
// output
for (int i = 0; i < elements.size(); i++) {
System.out.println(String.format("Element %d: %s", i + 1, elements.get(i)));
}
}
}
Output:
输出：
Element 1: 1-50
Element 2: of
Element 3: 500+
回答by user2804925
To fix the space problem, after splitting, you can use .trim()to remove the white space.
解决空间问题，拆分后，可以使用.trim()删除空白。
Something like this should work.
像这样的事情应该有效。
for(int x=0; x<stringArray.length(); x++){
stringArray[x] = stringArray[x].trim();
}
回答by sirmagid
import java.util.*;
import java.lang.*;
import java.io.*;
/* Name of the class has to be "Main" only if the class is public. */
class Ideone
{
public static void main (String[] args) throws java.lang.Exception
{
String string = "1-50 of 500+";
String[] stringArray = string.split("\s+");
for (String str : stringArray)
{
System.out.println(str);
}
}
}
