将参数从表单传递给控制器 Laravel
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Pass parameter from form to Controller Laravel
提问by FilippoLcr
I'm trying to understand how to pass parameters via URL in Laravel.
我试图了解如何在 Laravel 中通过 URL 传递参数。
In my case I've a home page (/) (HomeController@get__home and view home) that contains n data get from a database table. The user can select one of them and go to the next page.
就我而言，我有一个主页 (/)（HomeController@get__home 和 view home），其中包含从数据库表中获取的 n 个数据。用户可以选择其中一个并转到下一页。
The second url page is /{param from first page}/login
第二个 url 页面是 /{param from first page}/login
The field {param from first page} comes from (of course) first page and depends on which record was selected.
字段 {param from first page} 来自（当然）第一页，取决于选择的记录。
I've read this, but I think I'm out of the way.
我读过这个，但我想我已经不在了。
I can not find a way to pass the parameter to the url.
我找不到将参数传递给 url 的方法。
In my Route.php:
在我的 Route.php 中：
Route::get("/", "HomeController@home");
Route::get("/{position}/login", "LoginController@login");
and in Controllers:
并在控制器中：
class HomeController extends Controller
{
public function home(){
$foos = Foo::all();
return view('home')->with('foos',$foos);
}
}
class LoginController extends Controller
{
public function login(Foo $foo)
{
return view('login');
}
}
and in home.blade.php
并在 home.blade.php
<form class="" action="{{action(LoginController@login)}}" method="post">
...
回答by Laerte
Since you're using a form with post method, you should define the route like this:
由于您使用的是带有 post 方法的表单，因此您应该像这样定义路由：
Route::post("/login", "LoginController@login");
And then call it in the form action:
然后在表单操作中调用它：
<form action="{{action('LoginController@login')}}" method="post">
<select name="position">
<option value="1">Position 1</option>
<option value="2">Position 2</option>
</select>
...
Then, in the controller, you can get the option in the request:
然后，在控制器中，您可以获得请求中的选项：
class LoginController extends Controller
{
public function login(Request $request)
{
$position = $request->position;
return view('login');
}
}
