Android 如何格式化GPS经纬度？
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How to format GPS latitude and longitude?
提问by user3182266
In android(java) when you get the current latitude and longitude using the function getlatitude() etc you get the coordinates in decimal format:
在 android(java) 中，当您使用函数 getlatitude() 等获取当前纬度和经度时，您将获得十进制格式的坐标：
latitude: 24.3454523 longitude: 10.123450
纬度：24.3454523 经度：10.123450
I want to get this into degrees and decimal minutes to look something like this:
我想把它变成度数和十进制分钟，看起来像这样：
Latitude: 40°42′51″ N Longitude: 74°00′21″ W
纬度：40°42′51″ N 经度：74°00′21″ W
回答by dinesh sharma
to conver from decimals to degrees you can do as follow
要将小数转换为度数，您可以执行以下操作
String strLongitude = Location.convert(location.getLongitude(), Location.FORMAT_DEGREES);
String strLatitude = Location.convert(location.getLatitude(), Location.FORMAT_DEGREES);
reference is android developer site.
参考是android 开发者网站。
Edit
编辑
I have tried following thing and get the output:
我尝试了以下内容并获得输出：
strLongitude = Location.convert(location.getLongitude(), Location.FORMAT_DEGREES);
strLatitude = Location.convert(location.getLatitude(), Location.FORMAT_DEGREES);
OUTPUT : Long: 73.16584: Lat: 22.29924
strLongitude = Location.convert(location.getLongitude(), Location.FORMAT_SECONDS);
strLatitude = Location.convert(location.getLatitude(), Location.FORMAT_SECONDS);
OUTPUT : Long: 73:9:57.03876: Lat: 22:17:57.26472
strLongitude = Location.convert(location.getLongitude(), Location.FORMAT_MINUTES);
strLatitude = Location.convert(location.getLatitude(), Location.FORMAT_MINUTES);
OUTPUT : Long: 73:9.95065: Lat: 22:17.95441
Try different option as per your requirement
根据您的要求尝试不同的选项
回答by mshoaiblibra
Should be some math:
应该是一些数学：
(int)37.33168 => 37
37.33168 % 1 = 0.33168
0.33168 * 60 = 19.905 => 19
19.905 % 1 = 0.905
0.905 * 60 => 54
same with -122 (add 360 if negative value)
与 -122 相同（如果为负值，则添加 360）
EDIT:May be there is some API, which I don't know.
编辑：可能有一些我不知道的 API。
Refer From:How to find degree from the latitude value in android?
Convert Latitude and Longitude Values (Degrees) to Double . Java
回答by Martin
As already mentioned, there are some string manipulations required. I created the following helper class, which converts the location to DMS format and allows to specify the decimal places for the seconds:
如前所述，需要进行一些字符串操作。我创建了以下帮助程序类，它将位置转换为 DMS 格式并允许指定秒的小数位：
import android.location.Location;
import android.support.annotation.NonNull;
public class LocationConverter {
public static String getLatitudeAsDMS(Location location, int decimalPlace){
String strLatitude = Location.convert(location.getLatitude(), Location.FORMAT_SECONDS);
strLatitude = replaceDelimiters(strLatitude, decimalPlace);
strLatitude = strLatitude + " N";
return strLatitude;
}
public static String getLongitudeAsDMS(Location location, int decimalPlace){
String strLongitude = Location.convert(location.getLongitude(), Location.FORMAT_SECONDS);
strLongitude = replaceDelimiters(strLongitude, decimalPlace);
strLongitude = strLongitude + " W";
return strLongitude;
}
@NonNull
private static String replaceDelimiters(String str, int decimalPlace) {
str = str.replaceFirst(":", "°");
str = str.replaceFirst(":", "'");
int pointIndex = str.indexOf(".");
int endIndex = pointIndex + 1 + decimalPlace;
if(endIndex < str.length()) {
str = str.substring(0, endIndex);
}
str = str + "\"";
return str;
}
}
回答by planetmik
Here's a Kotlin version, adapted from Martin Weber's answer. It also sets the correct hemisphere; N, S, W or E
这是一个 Kotlin 版本，改编自 Martin Weber 的回答。它还设置了正确的半球；N、S、W 或 E
object LocationConverter {
fun latitudeAsDMS(latitude: Double, decimalPlace: Int): String {
val direction = if (latitude > 0) "N" else "S"
var strLatitude = Location.convert(latitude.absoluteValue, Location.FORMAT_SECONDS)
strLatitude = replaceDelimiters(strLatitude, decimalPlace)
strLatitude += " $direction"
return strLatitude
}
fun longitudeAsDMS(longitude: Double, decimalPlace: Int): String {
val direction = if (longitude > 0) "W" else "E"
var strLongitude = Location.convert(longitude.absoluteValue, Location.FORMAT_SECONDS)
strLongitude = replaceDelimiters(strLongitude, decimalPlace)
strLongitude += " $direction"
return strLongitude
}
private fun replaceDelimiters(str: String, decimalPlace: Int): String {
var str = str
str = str.replaceFirst(":".toRegex(), "°")
str = str.replaceFirst(":".toRegex(), "'")
val pointIndex = str.indexOf(".")
val endIndex = pointIndex + 1 + decimalPlace
if (endIndex < str.length) {
str = str.substring(0, endIndex)
}
str += "\""
return str
}
}
回答by abi
Use This
用这个
public static String getFormattedLocationInDegree(double latitude, double longitude) {
try {
int latSeconds = (int) Math.round(latitude * 3600);
int latDegrees = latSeconds / 3600;
latSeconds = Math.abs(latSeconds % 3600);
int latMinutes = latSeconds / 60;
latSeconds %= 60;
int longSeconds = (int) Math.round(longitude * 3600);
int longDegrees = longSeconds / 3600;
longSeconds = Math.abs(longSeconds % 3600);
int longMinutes = longSeconds / 60;
longSeconds %= 60;
String latDegree = latDegrees >= 0 ? "N" : "S";
String lonDegrees = longDegrees >= 0 ? "E" : "W";
return Math.abs(latDegrees) + "°" + latMinutes + "'" + latSeconds
+ "\"" + latDegree +" "+ Math.abs(longDegrees) + "°" + longMinutes
+ "'" + longSeconds + "\"" + lonDegrees;
} catch (Exception e) {
return ""+ String.format("%8.5f", latitude) + " "
+ String.format("%8.5f", longitude) ;
}
}
}
回答by AlexWien
You have a coordinate in decimal degrees, this representation format is called "DEG"
您有一个十进制度数的坐标，这种表示格式称为“DEG”
And you want a DEG to DMS (Degrees, Minutes, Seconds) (e.g 40°42′51″ N) ,
conversion.
并且您需要 DEG 到 DMS（度、分、秒）（例如 40°42′51″ N）的
转换。
This java code implementation at http://en.wikipedia.org/wiki/Geographic_coordinate_conversion
这个java代码实现在http://en.wikipedia.org/wiki/Geographic_coordinate_conversion
if the DEG coordinate values is < 0, it is West for longitude or South for latitude.
如果 DEG 坐标值 < 0，则经度为西或纬度为南。
