eclipse 带有休眠错误的 JPA：[PersistenceUnit: JPA] 无法构建 EntityManagerFactory
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JPA With Hibernate Error: [PersistenceUnit: JPA] Unable to build EntityManagerFactory
提问by Davidin073
I have a problem with Java Persistence API and Hibernate. My situation of project is:
我有 Java Persistence API 和 Hibernate 的问题。我的项目情况是：
My persistence.xml file is:
我的 persistence.xml 文件是：
<persistence
xmlns="http://java.sun.com/xml/ns/persistence"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd"
version="2.0">
<persistence-unit name="JPA">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<class>com.david.Libro</class>
<class>com.david.Categoria</class>
<properties>
<property name="hibernate.show_sql" value="true" />
<property name="javax.persistence.transactionType" value="RESOURCE_LOCAL" />
<property name="javax.persistence.jdbc.driver" value="com.mysql.jdbc.Driver" />
<property name="javax.persistence.jdbc.url" value="jdbc:mysql://localhost/arquitecturaJava" />
<property name="javax.persistence.jdbc.user" value="root" />
<property name="javax.persistence.jdbc.password" value="root" />
<property name="hibernate.dialect" value="org.hibernate.dialect.MySQL5Dialect" />
</properties>
</persistence-unit>
</persistence>
And i create EntityManagerFactory in:
我在以下位置创建 EntityManagerFactory：
private static EntityManagerFactory buildEntityManagerFactory()
{
try
{
return Persistence.createEntityManagerFactory("JPA");
}
catch (Throwable ex)
{
ex.printStackTrace();
//throw new RuntimeException("Error al crear la factoria de JPA:->"+ ex.getMessage());
}
}
My error is about create EntityManagerFactory:
我的错误是关于创建 EntityManagerFactory：
javax.persistence.PersistenceException: [PersistenceUnit: JPA] Unable to build EntityManagerFactory
at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:924)
at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:899)
at org.hibernate.ejb.HibernatePersistence.createEntityManagerFactory(HibernatePersistence.java:59)
at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:63)
at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:47)
at com.david.JPAHelper.buildEntityManagerFactory(JPAHelper.java:14)
at com.david.JPAHelper.<clinit>(JPAHelper.java:8)
at com.david.Categoria.buscarTodos(Categoria.java:93)
at com.david.FormularioInsertarLibroAccion.ejecutar(FormularioInsertarLibroAccion.java:25)
at com.david.ControladorLibros.doGet(ControladorLibros.java:38)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:621)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:728)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:305)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:210)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:222)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:123)
at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:472)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:171)
at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:99)
at org.apache.catalina.valves.AccessLogValve.invoke(AccessLogValve.java:947)
at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:118)
at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:408)
at org.apache.coyote.http11.AbstractHttp11Processor.process(AbstractHttp11Processor.java:1009)
at org.apache.coyote.AbstractProtocol$AbstractConnectionHandler.process(AbstractProtocol.java:589)
at org.apache.tomcat.util.net.JIoEndpoint$SocketProcessor.run(JIoEndpoint.java:310)
at java.util.concurrent.ThreadPoolExecutor.runWorker(Unknown Source)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(Unknown Source)
at java.lang.Thread.run(Unknown Source)
Caused by: org.hibernate.DuplicateMappingException: Duplicate class/entity mapping com.david.Libro
at org.hibernate.cfg.Configuration$MappingsImpl.addClass(Configuration.java:2638)
at org.hibernate.cfg.AnnotationBinder.bindClass(AnnotationBinder.java:706)
at org.hibernate.cfg.Configuration$MetadataSourceQueue.processAnnotatedClassesQueue(Configuration.java:3512)
at org.hibernate.cfg.Configuration$MetadataSourceQueue.processMetadata(Configuration.java:3466)
at org.hibernate.cfg.Configuration.secondPassCompile(Configuration.java:1355)
at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1756)
at org.hibernate.ejb.EntityManagerFactoryImpl.<init>(EntityManagerFactoryImpl.java:96)
at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:914)
... 27 more
Part of Libro and Categoria classes code is:
Libro 和 Categoria 类代码的一部分是：
@Entity
@Table(name = "Categorias")
public class Categoria implements Serializable
{
private static final long serialVersionUID = 1L;
@Id
@JoinColumn(name = "categoria")
private String id;
private String descripcion;
....
and
和
@Entity
@Table(name="Libros")
public class Libro implements Serializable
{
private static final long serialVersionUID = 1L;
@Id
private String isbn;
private String titulo;
@ManyToOne
@JoinColumn (name="categoria")
private Categoria categoria;
....
My file of Hibernate Configuration is:
我的休眠配置文件是：
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-configuration PUBLIC "-//Hibernate/Hibernate Configuration DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd">
<hibernate-configuration>
<session-factory>
<property name="connection.driver_class">com.mysql.jdbc.Driver</property>
<property name="connection.url">jdbc:mysql://localhost/arquitecturajava</property>
<property name="connection.username">root</property>
<property name="connection.password">root</property>
<property name="connection.pool_size">5</property>
<property name="dialect">org.hibernate.dialect.MySQL5Dialect</property>
<property name="show_sql">true</property>
<mapping class="com.david.Categoria"></mapping>
<mapping class="com.david.Libro"></mapping>
</session-factory>
</hibernate-configuration>
Any ideas!! Thank′s!!
有任何想法吗！！谢谢！！
回答by Balázs Németh
You don't need both hibernate.cfg.xmland persistence.xmlin this case. Have you tried removing hibernate.cfg.xmland mapping everything in persistence.xmlonly?
你并不需要同时hibernate.cfg.xml和persistence.xml在这种情况下。您是否尝试过仅删除hibernate.cfg.xml和映射所有内容persistence.xml？
But as the other answer also pointed out, this is not okay like this:
但正如另一个答案所指出的，这不是这样的：
@Id
@JoinColumn(name = "categoria")
private String id;
Didn't you want to use @Columninstead?
你不是想用@Column吗？
回答by eternay
Suppress the @JoinColumn(name="categoria")on the ID field of the Categoriaclass and I think it will work.
抑制类@JoinColumn(name="categoria")的 ID 字段，Categoria我认为它会起作用。
回答by Bharath Valse
It worked for me after adding the following dependency in pom,
在 pom 中添加以下依赖项后，它对我有用，
<dependency>
<groupId>org.hibernate</groupId>
<artifactId>hibernate-validator</artifactId>
<version>4.3.0.Final</version>
</dependency>回答by Vinit Bhardwaj
Use above annotation if someone is facing :--org.hibernate.jpa.HibernatePersistenceProvider persistence provider when it attempted to create the container entity manager factory for the paymentenginePU persistence unit. The following error occurred: [PersistenceUnit: paymentenginePU] Unable to build Hibernate SessionFactory ** This is a solution if you are using Audit table.@Audit
如果有人在尝试为支付引擎PU 持久性单元创建容器实体管理器工厂时遇到 :--org.hibernate.jpa.HibernatePersistenceProvider 持久性提供者，请使用上面的注释。发生以下错误：[PersistenceUnit: paymentenginePU] Unable to build Hibernate SessionFactory ** 如果您使用的是审计表，这是一个解决方案。@Audit
Use:- @Audited(targetAuditMode = RelationTargetAuditMode.NOT_AUDITED) on superclass.
使用：- @Audited(targetAuditMode = RelationTargetAuditMode.NOT_AUDITED) 在超类上。
