C++ 将 std::wstring 转换为 int
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Converting a std::wstring to int
提问by user3434662
I presume this to be very simple but I cannot get it to work.
我认为这很简单，但我无法让它工作。
I am simply trying to convert a std::wstring to an int.
我只是想将 std::wstring 转换为 int。
I have tried two methods so far.
到目前为止，我已经尝试了两种方法。
The first is to use the "C" method with "atoi" like so:
第一种是将“C”方法与“atoi”一起使用，如下所示：
int ConvertedInteger = atoi(OrigWString.c_str());
However, VC++ 2013 tells me:
但是，VC++ 2013 告诉我：
Error, argument of type "const wchar_t *" is incompatable with parameter of type "const char_t *"
错误，“const wchar_t *”类型的参数与“const char_t *”类型的参数不兼容
So my second method was to use this, per Google search:
所以我的第二种方法是使用这个，每个谷歌搜索：
std::wistringstream win(L"10");
int ConvertedInteger;
if (win >> ConvertedInteger && win.eof())
{
// The eof ensures all stream was processed and
// prevents acccepting "10abc" as valid ints.
}
However VC++ 2013 tells me this:
然而 VC++ 2013 告诉我这一点：
"Error: incomplete type not allowed."
“错误：不允许不完整的类型。”
What am I doing wrong here?
我在这里做错了什么？
Is there a better way to convert a std::wstring to int and back?
有没有更好的方法将 std::wstring 转换为 int 并返回？
Thank you for your time.
感谢您的时间。
回答by Thomas Petit
No need to revert to C api (atoi), or non portable API (_wtoi), or complex solution (wstringstream) because there are already simple, standard APIs to do this kind of conversion : std::stoiand std::to_wstring.
无需恢复到 C api ( atoi)、非可移植 API ( _wtoi) 或复杂的解决方案 ( wstringstream)，因为已经有简单的标准 API 来进行这种转换：std::stoi和std::to_wstring。
#include <string>
std::wstring ws = L"456";
int i = std::stoi(ws); // convert to int
std::wstring ws2 = std::to_wstring(i); // and back to wstring
回答by A B
you can use available API from wstring.h.
您可以使用来自wstring.h.
to convert WStringto inttry int ConvertedInteger = _wtoi(OrigWString);.
转换WString为inttry int ConvertedInteger = _wtoi(OrigWString);。
for reference use msdn.microsoft.com/en-us/library/aa273408(v=vs.60).aspx.
参考使用 msdn.microsoft.com/en-us/library/aa273408(v=vs.60).aspx。
