Python3 判断两个字典是否相等
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Python3 Determine if two dictionaries are equal
提问by Marc Wagner
This seems trivial, but I cannot find a built-in or simple way to determine if two dictionaries are equal.
这似乎微不足道，但我找不到确定两个字典是否相等的内置或简单方法。
What I want is:
我想要的是：
a = {'foo': 1, 'bar': 2}
b = {'foo': 1, 'bar': 2}
c = {'bar': 2, 'foo': 1}
d = {'foo': 2, 'bar': 1}
e = {'foo': 1, 'bar': 2, 'baz':3}
f = {'foo': 1}
equal(a, b) # True
equal(a, c) # True - order does not matter
equal(a, d) # False - values do not match
equal(a, e) # False - e has additional elements
equal(a, f) # False - a has additional elements
I could make a short looping script, but I cannot imagine that mine is such a unique use case.
我可以制作一个简短的循环脚本，但我无法想象我的脚本是如此独特的用例。
回答by Sharvin26
==works
==作品
a = dict(one=1, two=2, three=3)
b = {'one': 1, 'two': 2, 'three': 3}
c = dict(zip(['one', 'two', 'three'], [1, 2, 3]))
d = dict([('two', 2), ('one', 1), ('three', 3)])
e = dict({'three': 3, 'one': 1, 'two': 2})
a == b == c == d == e
True
I hope the above example helps you.
我希望上面的例子对你有帮助。
回答by Constantine32
The good old ==statement works.
好的旧==语句有效。
回答by Srce Cde
a = {'foo': 1, 'bar': 2}
b = {'foo': 1, 'bar': 2}
c = {'bar': 2, 'foo': 1}
d = {'foo': 2, 'bar': 1}
e = {'foo': 1, 'bar': 2, 'baz':3}
f = {'foo': 1}
print(a.items() == b.items())
print(a.items() == c.items())
print(a.items() == d.items())
print(a.items() == e.items())
print(a.items() == f.items())
Output
输出
True
True
False
False
False
