SQL 获取sql server中的表和索引存储大小
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Get Table and Index storage size in sql server
提问by Arian
I want to get table data and index space for every table in my database:
我想为我的数据库中的每个表获取表数据和索引空间:
Table Name Data Space Index Space
-------------------------------------------------------
How can I achieve this result?
我怎样才能达到这个结果?
回答by marc_s
This query here will list the total size that a table takes up - clustered index, heap and all nonclustered indices:
此处的查询将列出表占用的总大小 - 聚集索引、堆和所有非聚集索引:
SELECT
s.Name AS SchemaName,
t.NAME AS TableName,
p.rows AS RowCounts,
SUM(a.total_pages) * 8 AS TotalSpaceKB,
SUM(a.used_pages) * 8 AS UsedSpaceKB,
(SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB
FROM
sys.tables t
INNER JOIN
sys.schemas s ON s.schema_id = t.schema_id
INNER JOIN
sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN
sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN
sys.allocation_units a ON p.partition_id = a.container_id
WHERE
t.NAME NOT LIKE 'dt%' -- filter out system tables for diagramming
AND t.is_ms_shipped = 0
AND i.OBJECT_ID > 255
GROUP BY
t.Name, s.Name, p.Rows
ORDER BY
s.Name, t.Name
If you want to separate table space from index space, you need to use AND i.index_id IN (0,1)
for the table space (index_id = 0
is the heap space, index_id = 1
is the size of the clustered index = data pages) and AND i.index_id > 1
for the index-only space
如果要将表空间与索引空间分开,则需要AND i.index_id IN (0,1)
用于表空间(index_id = 0
是堆空间,index_id = 1
是聚集索引的大小=数据页)和AND i.index_id > 1
仅用于索引的空间
回答by muhmud
with pages as (
SELECT object_id, SUM (reserved_page_count) as reserved_pages, SUM (used_page_count) as used_pages,
SUM (case
when (index_id < 2) then (in_row_data_page_count + lob_used_page_count + row_overflow_used_page_count)
else lob_used_page_count + row_overflow_used_page_count
end) as pages
FROM sys.dm_db_partition_stats
group by object_id
), extra as (
SELECT p.object_id, sum(reserved_page_count) as reserved_pages, sum(used_page_count) as used_pages
FROM sys.dm_db_partition_stats p, sys.internal_tables it
WHERE it.internal_type IN (202,204,211,212,213,214,215,216) AND p.object_id = it.object_id
group by p.object_id
)
SELECT object_schema_name(p.object_id) + '.' + object_name(p.object_id) as TableName, (p.reserved_pages + isnull(e.reserved_pages, 0)) * 8 as reserved_kb,
pages * 8 as data_kb,
(CASE WHEN p.used_pages + isnull(e.used_pages, 0) > pages THEN (p.used_pages + isnull(e.used_pages, 0) - pages) ELSE 0 END) * 8 as index_kb,
(CASE WHEN p.reserved_pages + isnull(e.reserved_pages, 0) > p.used_pages + isnull(e.used_pages, 0) THEN (p.reserved_pages + isnull(e.reserved_pages, 0) - p.used_pages + isnull(e.used_pages, 0)) else 0 end) * 8 as unused_kb
from pages p
left outer join extra e on p.object_id = e.object_id
Takes into account internal tables, such as those used for XML storage.
考虑内部表,例如用于 XML 存储的表。
Edit: If you divide the data_kb
and index_kb
values by 1024.0, you will get the numbers you see in the GUI.
编辑:如果将data_kb
和index_kb
值除以 1024.0,您将获得在 GUI 中看到的数字。