用于启动 URL 的 Xcode 按钮
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Xcode Button to Launch URL
提问by user1532706
I've created a simple app that has a button in the bottom toolbar and I can't seem to get the button to work. I've tried to attach an action to it that will open a URL when pressed but it did not work. So I've removed that action and I'm hoping someone can help. I've posted the compressed xcode project at this URL https://www.box.com/s/5d45ce1df7d9dd0fe205
我创建了一个简单的应用程序，在底部工具栏中有一个按钮，但我似乎无法让该按钮工作。我试图给它附加一个动作，当按下时它会打开一个 URL，但它没有用。因此，我已删除该操作，希望有人可以提供帮助。我已经在这个 URL https://www.box.com/s/5d45ce1df7d9dd0fe205 上发布了压缩的 xcode 项目
Any help is appreciated.
任何帮助表示赞赏。
回答by Anthony
Something like this would work. This is an example of a text-only button:
像这样的事情会起作用。这是纯文本按钮的示例：
UIButton *button = [UIButton buttonWithType:UIButtonTypeCustom];
[button setFrame:CGRectMake(0, 0, 100, 40)];
[button setBackgroundColor:[UIColor clearColor]];
[button setTitle:@"Google" forState:UIControlStateNormal];
[button setTitleColor:[UIColor blueColor] forState:UIControlStateNormal];
[button addTarget:self action:@selector(openGoogleURL) forControlEvents:UIControlEventTouchUpInside];
[self.view addSubview:button];
And the button's selector:
和按钮的选择器：
-(void)openGoogleURL
{
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"https://www.google.com"]];
}
回答by changtung
Use another viewcontroller with webView embeeded. This solution force to stay in your application during watching url content.
使用另一个嵌入了 webView 的视图控制器。此解决方案强制在观看 url 内容期间留在您的应用程序中。
- Create another view controller on storyboard.
- place webview on it. ( name it webView )
- connect web view with controller class through assistant editor ( assuming that You connected new UIView class to view controller )
in viewDidLoad of your new class insert:
[super viewDidLoad]; NSString *fullURL = @"http://google.pl"; NSURL *url = [NSURL URLWithString:fullURL]; NSURLRequest *requestObj = [NSURLRequest requestWithURL:url]; [self.webView loadRequest:requestObj];
- 在情节提要上创建另一个视图控制器。
- 将 webview 放在上面。（将其命名为 webView ）
- 通过辅助编辑器将 web 视图与控制器类连接（假设您将新的 UIView 类连接到视图控制器）
在新类的 viewDidLoad 中插入：
[super viewDidLoad]; NSString *fullURL = @"http://google.pl"; NSURL *url = [NSURL URLWithString:fullURL]; NSURLRequest *requestObj = [NSURLRequest requestWithURL:url]; [self.webView loadRequest:requestObj];
