如何在数组中查找多个元素 - Javascript，ES6
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How to find multiple elements in Array - Javascript ,ES6
提问by Gowtham S
Code:
代码：
let names= ["Style","List","Raw"];
let results= names.find(x=> x.includes("s");
console.log(results); //
How to get the names which contain "s" from the array names, currently, I am getting only one element as a result but i need all occurrences.
如何从数组名称中获取包含“s”的名称，目前，我只得到一个元素，但我需要所有出现的元素。
回答by Rajaprabhu Aravindasamy
You have to use filterat this context,
你必须filter在这种情况下使用，
let names= ["Style","List","Raw"];
let results= names.filter(x => x.includes("s"));
console.log(results); //["List"]
If you want it to be case insensitive then use the below code,
如果您希望它不区分大小写，请使用以下代码，
let names= ["Style","List","Raw"];
let results= names.filter(x => x.toLowerCase().includes("s"));
console.log(results); //["Style", "List"]
To make it case in sensitive, we have to make the string's character all to lower case.
为了区分大小写，我们必须将字符串的字符全部设为小写。
回答by ingleback
Use filter instead of find.
使用过滤器代替查找。
let names= ["Style","List","Raw"];
let results= names.filter(x => x.includes("s"));
console.log(results);
回答by kevin ternet
But you can also use forEach() method :
但您也可以使用 forEach() 方法：
var names = ["Style","List","Raw"];
var results = [];
names.forEach(x => {if (x.includes("s") || x.includes("S")) results.push(x)});
console.log(results); // [ 'Style', 'List' ]
Or if you prefere :
或者，如果您更喜欢：
names.forEach(x => {if (x.toLowerCase().includes("s")) results.push(x)});
