我如何使用 tabindex 找到元素 - Javascript 而不是 jquery
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How can i find an element using tabindex - Javascript not jquery
提问by zod
I am trying to move focus to the next element after data is entered in one element.
在一个元素中输入数据后,我试图将焦点移到下一个元素。
How can i get the next element using tabindex and move focus.
如何使用 tabindex 获取下一个元素并移动焦点。
i am using scanner for data entry. so one second delay on key up will tell data entered or not. As it is scanner no browser tabbing by user .
我正在使用扫描仪进行数据输入。所以按键延迟一秒会告诉数据输入与否。由于它是扫描仪,用户没有浏览器标签。
<tr>
<td class='form' align='center'> <input type='text' tabindex=1 onkeyup='moveNext(this);' id='from' name='elem1' size='5' value=''> </td>
<td class='form' align='center'><input type='text' tabindex=2 onkeyup='moveNext(this);' id='item' name='elem2' size='5' value=''> </td>
<td class='form' align='center' > <input type='text' tabindex=3 id='calc_price' size='10' name='elem3' value=''> </td>
</tr>
I saw some answers. All in jquery . How can i do that in javascript
我看到了一些答案。全部在 jquery 中。我怎么能在javascript中做到这一点
回答by adeneo
You'd have to get the tabindex of the current element, add 1 and then search for an element with that tabindex to set the focus to :
您必须获取当前元素的 tabindex,加 1,然后搜索具有该 tabindex 的元素以将焦点设置为:
function moveNext(elem) {
var tidx = +(elem.getAttribute('tabindex')) +1,
elems = document.getElementsByTagName('input');
for (var i=elems.length; i--;) {
var tidx2 = elems[i].getAttribute('tabindex');
if (tidx2 == tidx) elems[i].focus();
}
}
回答by Elliott Frisch
How about something like this
这样的事情怎么样
function moveNext(tabInput) {
var lastTab = 3;
var curIndex = tabInput.tabIndex;
var tabs = document.getElementsByTagName("input");
if(curIndex >= lastTab) { //if we are on the last tab then go back to the beginning
curIndex = 0;
}
for(var i=0; i < tabs.length; i++) { // loop over the tabs.
if(tabs[i].tabIndex == (curIndex+1)) { // is this our tab?
tabbables[i].focus(); // Focus and leave.
break;
}
}
回答by tremby
Here's an implementation I just wrote. It's a bit more sophisticated in that it filters out hidden and disabled inputs, and handles multiple elements with the same tab index. It's tested only in Firefox so far.
这是我刚刚写的一个实现。它更复杂一点,因为它过滤掉隐藏和禁用的输入,并处理具有相同标签索引的多个元素。到目前为止,它仅在 Firefox 中进行了测试。
Coffee:
咖啡:
getElementsInTabOrder = (form) ->
# Get all focusable form elements
elements = Array.prototype.filter.call form.elements, (element) ->
return false if element.type is 'hidden'
return false if element.disabled
return true
# Get elements grouped by tab index
elementsByTabIndex = []
for element in elements
tabIndex = element.tabIndex
unless elementsByTabIndex[tabIndex]?
elementsByTabIndex[tabIndex] = []
elementsByTabIndex[tabIndex].push element
# Flatten to output array
return [].concat elementsByTabIndex...
getElementByDelta = (element, delta, wrap = true) ->
elements = getElementsInTabOrder element.form
length = elements.length
index = elements.indexOf element
targetIndex = index + delta
# Deal with edge cases
while targetIndex < 0
return null unless wrap
targetIndex += length
while targetIndex >= length - 1
return null unless wrap
targetIndex -= length
return elements[targetIndex]
getNextElement = (element, wrap = true) ->
return getElementByDelta element, 1, wrap
getPreviousElement = (element, wrap = true) ->
return getElementByDelta element, -1, wrap
module.exports = {
getElementsInTabOrder
getElementByDelta
getNextElement
getPreviousElement
}
Javascript:
Javascript:
// Generated by CoffeeScript 1.10.0
var getElementByDelta, getElementsInTabOrder, getNextElement, getPreviousElement;
getElementsInTabOrder = function(form) {
var element, elements, elementsByTabIndex, i, len, ref, tabIndex;
elements = Array.prototype.filter.call(form.elements, function(element) {
if (element.type === 'hidden') {
return false;
}
if (element.disabled) {
return false;
}
return true;
});
elementsByTabIndex = [];
for (i = 0, len = elements.length; i < len; i++) {
element = elements[i];
tabIndex = element.tabIndex;
if (elementsByTabIndex[tabIndex] == null) {
elementsByTabIndex[tabIndex] = [];
}
elementsByTabIndex[tabIndex].push(element);
}
return (ref = []).concat.apply(ref, elementsByTabIndex);
};
getElementByDelta = function(element, delta, wrap) {
var elements, index, length, targetIndex;
if (wrap == null) {
wrap = true;
}
elements = getElementsInTabOrder(element.form);
length = elements.length;
index = elements.indexOf(element);
targetIndex = index + delta;
while (targetIndex < 0) {
if (!wrap) {
return null;
}
targetIndex += length;
}
while (targetIndex >= length - 1) {
if (!wrap) {
return null;
}
targetIndex -= length;
}
return elements[targetIndex];
};
getNextElement = function(element, wrap) {
if (wrap == null) {
wrap = true;
}
return getElementByDelta(element, 1, wrap);
};
getPreviousElement = function(element, wrap) {
if (wrap == null) {
wrap = true;
}
return getElementByDelta(element, -1, wrap);
};
module.exports = {
getElementsInTabOrder: getElementsInTabOrder,
getElementByDelta: getElementByDelta,
getNextElement: getNextElement,
getPreviousElement: getPreviousElement
};