使用 PHP 用正则表达式替换正则表达式
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Using PHP replace regex with regex
提问by user1272589
I want to replace hash tags in a string with the same hash tag, but after adding a link to it
我想用相同的散列标签替换字符串中的散列标签，但在添加链接后
Example:
例子：
$text = "any word here related to #English must #be replaced."
I want to replace each hashtag with
我想用
#English ---> <a href="bla bla">#English</a>
#be ---> <a href="bla bla">#be</a>
So the output should be like that:
所以输出应该是这样的：
$text = "any word here related to <a href="bla bla">#English</a> must <a href="bla bla">#be</a> replaced."
回答by Nambi
回答by Ja?ck
This should nudge you in the right direction:
这应该会推动您朝着正确的方向前进：
echo preg_replace_callback('/#(\w+)/', function($match) {
return sprintf('<a href="https://www.google.com?q=%s">%s</a>',
urlencode($match[1]),
htmlspecialchars($match[0])
);
}, htmlspecialchars($text));
See also: preg_replace_callback()
也可以看看： preg_replace_callback()
回答by Wiktor Stribi?ew
If you need to refer to the whole match from the string replacement pattern all you need is a $0placeholder, also called replacemenf backreference.
如果您需要从字符串替换模式中引用整个匹配项，您只需要一个$0占位符，也称为 replacemenf 反向引用。
So, you want to wrap a match with some text and your regex is #\w+, then use
所以，你想用一些文本包裹一个匹配，你的正则表达式是#\w+，然后使用
$text = "any word here related to #English must #be replaced.";
$text = preg_replace("/#\w+/", "<a href='bla bla'>preg_replace("/#(\w+)/", "<a href='path/##代码##'></a>", $text)
</a>", $text);
Note you may combine $0with $1, etc. In case you need to enclose a part of the match with some fixed strings you will have to use capturing groups. Say, you want to get access to both #Englishand Englishwithin one preg_replacecall. Then use
请注意，您可以$0与$1等组合使用。如果您需要将匹配的一部分与一些固定字符串括起来，您将不得不使用捕获组。假设您希望在一次通话中同时访问#English和访问。然后使用Englishpreg_replace
Output will be any word here related to <a href='path/#English'>English</a> must <a href='path/#be'>be</a> replace.
输出将为any word here related to <a href='path/#English'>English</a> must <a href='path/#be'>be</a> replace.
