php php数组中重复元素的数量

count of duplicate elements in an array in php

提问by I'm nidhin

Hi, How can we find the count of duplicate elements in a multidimensional array?

嗨，我们如何找到 a 中重复元素的数量multidimensional array？

I have an array like this

我有一个这样的数组

Array
(
    [0] => Array
        (
            [lid] => 192
            [lname] => sdsss
        )

    [1] => Array
        (
            [lid] => 202
            [lname] =>  testing
        )

    [2] => Array
        (
            [lid] => 192
            [lname] => sdsss
        )

    [3] => Array
        (
            [lid] => 202
            [lname] =>  testing
        )

)

How to find the count of each elements ?

如何找到每个元素的数量？

i.e, count of entries with id 192,202etc

即算有ID的条目192，202等

回答by Ja?ck

You can adopt this trick; map each item of the array (which is an array itself) to its respective ['lid']member and then use array_count_value()to do the counting for you.

你可以采用这个技巧；将数组的每个项目（它本身就是一个数组）映射到其各自的['lid']成员，然后用于array_count_value()为您进行计数。

array_count_values(array_map(function($item) {
    return $item['lid'];
}, $arr);

Plus, it's a one-liner, thus adding to elite hacker status.

另外，它是单线的，因此增加了精英黑客的地位。

Update

更新

Since 5.5 you can shorten it to:

从 5.5 开始，您可以将其缩短为：

array_count_values(array_column($arr, 'lid'));

回答by Cedrun

foreach ($array as $value) 
{
    $numbers[$value[lid]]++;
}
foreach ($numbers as $key => $value) 
{
    echo 'numbers of '.$key.' equal '.$value.'<br/>';
}

回答by shishir mishra

Following code will count duplicate element of an array.Please review it and try this code

以下代码将计算数组的重复元素。请查看并尝试此代码

 $arrayChars=array("green","red","yellow","green","red","yellow","green");

    $arrLength=count($arrayChars);
    $elementCount=array();
  for($i=0;$i<$arrLength-1;$i++)
    {
       $key=$arrayChars[$i];
      if($elementCount[$key]>=1)
       {
          $elementCount[$key]++;
       } else  {
          $elementCount[$key]=1;
       }


   }

   echo "<pre>";
   print_r($elementCount);

OUTPUT:
Array ( [green] => 3 [red] => 2 [yellow] => 2 )

输出：
数组（[绿色] => 3 [红色] => 2 [黄色] => 2）

You can also view similar questions with array handling on following link http://solvemyquest.com/count-duplicant-element-array-php-without-using-built-function/

您还可以在以下链接上查看与数组处理类似的问题 http://solvemyquest.com/count-duplicant-element-array-php-without-using-built-function/

回答by LeonardChallis

The following code will get the counts for all of them - anything > 1 at the end will be repeated.

以下代码将获得所有这些的计数 - 最后任何 > 1 的内容都将被重复。

<?php
$lidCount = array();
$lnameCount = array();

foreach ($yourArray as $arr) {

  if (isset($lidCount[$arr['lid']])) {
    $lidCount[$arr['lid']]++;
  } else {
    $lidCount[$arr['lid']] = 1;
  }

  if (isset($lnameCount [$arr['lname']])) {
    $lnameCount [$arr['lname']]++;
  } else {
    $lnameCount [$arr['lname']] = 1;
  }

}

回答by Arun

$array = array('192', '202', '192', '202');
print_r(array_count_values($array));

回答by rOcKiNg RhO

$orders = array(
 array(
    'lid' => '',
    'lname' => '',

  ))....
$foundIds = array();
foreach ( $orders as $index => $order )
{
  if ( isset( $foundIds[$order['lid']] ) )
  {
    $orders[$index]['is_dupe'] = true;
    $orders[$foundIds[$order['lid']]]['is_dupe'] = true;
  } else {
    $orders[$index]['is_dupe'] = false;
  }
  $foundIds[$order['lid']] = $index;
}

回答by Lao

Try this code :

试试这个代码：

$array_count = array();
foreach ($array as $arr) :
    if (in_array($arr, $array_count)) {
        foreach ($array_count as $key => $count) :
            if ($key == $arr) {
                $array_count[$key]++;
                break;
            }
        endforeach;
    } else {
        $array_count[$arr] = 1;
    }
endforeach;

回答by Anand Pal

Check with in_array()function.

检查in_array()功能。