Ruby-on-rails Rails - 获取不带 GET 参数的当前 url
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Rails - Get the current url without the GET parameters
提问by MrRuru
request.url returns me this : http://localhost:3000/page?foo=bar.
request.url 返回给我：http://localhost:3000/page?foo=bar。
Is there a method I can call to get http://localhost:3000/page, or do I have to parse the string to strip get parameters?
有没有我可以调用的方法来获取http://localhost:3000/page，或者我是否必须解析字符串以去除获取参数？
回答by tadman
request.pathshould return what you're looking for if you're not concerned about the hostname. Otherwise you might try:
request.path如果您不关心主机名，应该返回您要查找的内容。否则你可以尝试：
url_for(:only_path => false, :overwrite_params=>nil)
回答by Nerve
To get the request URL without any query parameters.
获取不带任何查询参数的请求 URL。
def current_url_without_parameters
request.base_url + request.path
end
回答by thekingoftruth
I use the following:
我使用以下内容：
request.original_url.split('?').first
It does not regenerate the path, and therefore gives you exactly the url that the end-user sees in their browser, minus query parameters.
它不会重新生成路径，因此为您提供最终用户在其浏览器中看到的 url，减去查询参数。
