TypeScript 函数箭头表达式返回对象

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时间:2020-09-13 16:14:26  来源:igfitidea点击:

TypeScript function arrow expression returning object

typescript

提问by Dace Zarina

I have such case:

我有这样的情况:

interface MoverShaker {
    getStatus(): { speed: number; frequency: number; };
}

function GetMoverShaker() : MoverShaker {
    return {
        getStatus: () => { speed: 2, frequency: 3 }
    }
}

I am getting such error: The name 'frequency' does not exist in the current scope. Is such construction possible in TypeScript? If I am using such construction then everything is ok:

我收到这样的错误:当前范围中不存在名称“频率”。这样的构造在 TypeScript 中可行吗?如果我使用这样的结构,那么一切都很好:

function GetMoverShaker(): MoverShaker {
    return {
        getStatus: () => {
             return { speed: 2, frequency: 3 }
        }
}

回答by Roger Johansson

You can add parens:

您可以添加括号:

() => ({x:1,y:2})

This makes the parser understand that the { is not the beginning of a code block.

这使解析器明白 { 不是代码块的开始。