在java中删除字符串中的特殊字符？
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/21074485/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Remove special characters in the string in java?
提问by Minato
How to remove special characters in the string except "- _". Now I use:
如何删除字符串中除“-_”之外的特殊字符。现在我使用：
replaceAll("[^\w\s]", "")
it remove all special character but i want to keep "- _" . Can anyone tell me how should I do?
它删除了所有特殊字符，但我想保留 "- _" 。谁能告诉我该怎么办？
回答by zmbq
Use replaceAll("[^\\w\\s\\-_]", "");
用 replaceAll("[^\\w\\s\\-_]", "");
What I did was add the underscore and hyphen to the regular expression. I added a \\before the hyphen because it also serves for specifying ranges: a-zmeans all letters between a and z. Escaping it with \\makes sure it is treated as an hyphen.
我所做的是在正则表达式中添加下划线和连字符。我\\在连字符之前添加了 a ，因为它也用于指定范围：a-z表示 a 和 z 之间的所有字母。转义它\\确保它被视为连字符。
回答by nKn
This might help:
这可能有帮助：
replaceAll("[^a-zA-Z0-9_-]", "");
replaceAll("[^a-zA-Z0-9_-]", "");
回答by rupesh
Use this replaceAll("[\\w\\s\\-\\_\\<.*?>]", "");
使用这个replaceAll("[\\w\\s\\-\\_\\<.*?>]", "");
回答by Cuong
Pattern pt = Pattern.compile("[^a-zA-Z0-9_-]");
Matcher match = pt.matcher(c);
while (match.find()) {
String s = match.group();
c = c.replaceAll("\" + s, "");
}
Consider this
考虑这个
回答by Bohemian
I suspect that you need to assignthe result (in case you're not doing that), because replaceAll()returns a newstring, rather than updating the string (String is immutable):
我怀疑您需要分配结果（以防您不这样做），因为replaceAll()返回一个新字符串，而不是更新字符串（字符串是不可变的）：
str = str.replaceAll("[^\w\s-]", "");
Also note that the regex is quite simple:
另请注意，正则表达式非常简单：
No need to escape the dash -in the character class: When used as a literalin a character class, it must be either first or last (otherwise it indicates a range, like a-zetc).
无需转义-字符类中的破折号：当用作字符类中的文字时，它必须是第一个或最后一个（否则它表示一个范围，例如a-z等）。
No need to mention the underscore at all, because it is alreadylisted: \wincludesthe underscore character!
根本不需要提及下划线，因为它已经列出：\w包括下划线字符！
回答by Kajal Kumari
String str="owl@134_- abc";
String s=str.replaceAll(" [^a-zA-Z_-]+ ", "");
System.out.println(str);
It will replace the special character and white spaces from a given string.
它将替换给定字符串中的特殊字符和空格。
Output will be: owlabc_-
输出将是： owlabc_-
回答by Kaplan
barely 6 years have passed and we have a lambda solution
仅仅 6 年过去了，我们有了 lambda 解决方案
String str = "owl@134_- abc";
str.codePoints().mapToObj( Character::toChars ).filter(
a -> (a.length == 1 && (Character.isLetterOrDigit( a[0] ) || a[0] == '-' || a[0] == '_')) )
.collect( StringBuilder::new, StringBuilder::append, StringBuilder::append ).toString(); // owl134_-abc
