ios Iphone 删除子视图
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Iphone remove sub view
提问by Sharanya K M
I have a UINavigationController. On the right top i have a button on click of which i have to get a drop down table view. I created another UIViewController Class, with xib and added it as a subView to the current view. It should appear on 1st click and disappear on the 2nd click. This should happen for all click(open view and close view). I wrote this code but dont know where i'm going wrong. someone please help
我有一个 UINavigationController。在右上角，我有一个单击按钮，我必须获得一个下拉表格视图。我使用 xib 创建了另一个 UIViewController 类，并将其作为子视图添加到当前视图中。它应该在第一次点击时出现，在第二次点击时消失。这应该发生在所有点击（打开视图和关闭视图）上。我写了这段代码，但不知道我哪里出错了。有人请帮忙
-(void)modalTableView
{
tableView1 = [[TableViewController alloc] initWithNibName:@"TableViewController" bundle:nil];
for (UIView *subView in self.view.subviews)
{
if ([subView isKindOfClass:[TableViewController class]])
{
[subView removeFromSuperview];
}
else
{
[self.view addSubview:tableView1.view];
}
}
}
What am i missing here?
我在这里缺少什么？
EDIT : TableViewController is the name of my UIViewController Class
编辑：TableViewController 是我的 UIViewController 类的名称
回答by Damo
The clue is here
线索在这里
for (UIView *subView in self.view.subviews)
each subView is of class UIView and your test
每个子视图都属于 UIView 类和您的测试
isKindOfClass:[TableViewController class]
is testing for class TableViewController
正在测试 TableViewController 类
I would suggest a way of doing this would be by tagging the views that you add dynamically, with say 99 - and then in your loop you can identify those views by their tag.
我建议这样做的一种方法是标记您动态添加的视图，比如 99 - 然后在您的循环中，您可以通过它们的标签识别这些视图。
eg.
例如。
for (UIView *subView in self.view.subviews)
{
if (subView.tag == 99)
{
[subView removeFromSuperview];
}
}
回答by Suragch
Swift version
迅捷版
To remove a single subview:
删除单个子视图：
subView.removeFromSuperview()
To remove all subviews:
删除所有子视图：
for subView in self.subviews as [UIView] {
subView.removeFromSuperview()
}
Source: What is the best way to remove all views from parent view / super view?
回答by chinthakad
Try this,
尝试这个，
if ([subView isKindOfClass:[UITableView class]])
{
[subView removeFromSuperview];
}
回答by Damo
Here is something that should go some way to working - assuming that tableView1 is a retained @property (If not then maybe thisSO answer on lazy loading techniques is for you).
这里有一些应该以某种方式工作的东西 - 假设 tableView1 是一个保留的@property（如果不是，那么这个关于延迟加载技术的答案可能适合你）。
-(void)modalTableView
{
if (tableView1 != nil)
{
tableView1 = [[TableViewController alloc] initWithNibName:@"TableViewController" bundle:nil];
}
if (tableView1.view.superview == nil)
{
[self.view addSubview:tableView1.view];
} else
{
[tableView1.view removeFormSuperview];
}
}
