如何 Java 正则表达式匹配除指定模式之外的所有内容
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How to Java Regex to match everything but specified pattern
提问by vamsiampolu
I am trying to match everything but garbage values in the entire string.The pattern I am trying to use is:
我试图匹配整个字符串中除垃圾值之外的所有内容。我尝试使用的模式是：
^.*(?!\w|\s|-|\.|[@:,]).*$
I have been testing the pattern on regexPlanet and this seems to be matching the entire string.The input string I was using was:
我一直在 regexPlanet 上测试模式，这似乎与整个字符串匹配。我使用的输入字符串是：
Vamsi///#k03@g!!!l.com 123**5
How can I get it to only match everything but the pattern,I would like to replace any string that matches with an empty space or a special charecter of my choice.
我怎样才能让它只匹配除模式之外的所有内容，我想替换与空白或我选择的特殊字符匹配的任何字符串。
采纳答案by Bernhard Barker
The pattern, as written, is supposed to match the whole string.
所写的模式应该匹配整个字符串。
^- start of string..*- zero or more of any character.(?!\w|\s|-|\.|[@:,])- negative look-ahead for some characters..*- zero or more of any character.$- end of string.
^- 字符串的开始。.*- 零个或多个任何字符。(?!\w|\s|-|\.|[@:,])- 某些角色的负面展望。.*- 零个或多个任何字符。$- 字符串的结尾。
If you only want to match characters which aren't one of the supplied characters, try simply:
如果您只想匹配不是提供的字符之一的字符，请尝试简单：
[^-\w\s.@:,]
[^...]is a negated character class, it will match any characters not supplied in the brackets. See thisfor more information.
[^...]是一个否定字符类，它将匹配括号中未提供的任何字符。有关更多信息，请参阅此内容。
Test.
测试。
