wpf SaveFileDialog 上的 DialogResult.OK 不起作用
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DialogResult.OK on SaveFileDialog not work
提问by Hassan
I try, when I press save in SaveFileDialogI do something. I trying fix but always something wrong.
我尝试，当我按下保存时，SaveFileDialog我会做一些事情。我试图修复但总是有问题。
SaveFileDialog dlg2 = new SaveFileDialog();
dlg2.Filter = "xml | *.xml";
dlg2.DefaultExt = "xml";
dlg2.ShowDialog();
if (dlg2.ShowDialog() == DialogResult.OK)
{....}
But I have error on OK - which say:
但是我在 OK 上有错误 - 其中说：
Error: 'System.Nullable' does not contain a definition for 'OK' and no extension method 'OK' accepting a first argument of type 'System.Nullable' could be found (are you missing a using directive or an assembly reference?)
错误： “System.Nullable”不包含“OK”的定义，并且找不到接受“System.Nullable”类型的第一个参数的扩展方法“OK”（您是否缺少 using 指令或程序集引用？）
I try fix with this code:
我尝试使用此代码修复：
DialogResult result = dlg2.ShowDialog(); //here is error again
if (result == DialogResult.OK)
{....}
Now error is on DialogResult say: 'System.Windows.Window.DialogResult' is a 'property' but is used like a 'type'
现在错误是在 DialogResult 上说： 'System.Windows.Window.DialogResult' 是一个 'property' 但被用作一个 'type'
回答by Hassan
I assume that you are referring to WPFnot Windows FormHere is example of using SaveFileDialog
我假设您指的是WPFnot Windows FormHere is the example of usingSaveFileDialog
//configure save file dialog box
Microsoft.Win32.SaveFileDialog dlg = new Microsoft.Win32.SaveFileDialog();
dlg.FileName = "Document"; //default file name
dlg.DefaultExt = ".xml"; //default file extension
dlg.Filter = "XML documents (.xml)|*.xml"; //filter files by extension
// Show save file dialog box
Nullable<bool> result = dlg.ShowDialog();
// Process save file dialog box results
if (result == true)
{
// Save document
string filename = dlg.FileName;
}
Other Example:
其他示例：
In WPFyou have to handle conflict between DialogResultEnumeration and Window.DialogResultProperty
在WPF你要把手之间的冲突DialogResult枚举和Window.DialogResult属性
Try using fully qualified name to refer the enumeration:
尝试使用完全限定名称来引用枚举：
System.Windows.Forms.DialogResult result = dlg2.ShowDialog();
if (result == DialogResult.OK)
{....}
回答by Loran
DialogResultreturn System.Windows.Forms.DialogResult.So u can use like that=>
DialogResult返回System.Windows.Forms.DialogResult。所以你可以这样使用=>
DialogResult result = dlg2.ShowDialog();
if (result == System.Windows.Forms.DialogResult.OK)
{....}
