如何将包含时间的字符串变量转换为 C++ 中的 time_t 类型？
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How to convert a string variable containing time to time_t type in c++?
提问by R11G
I have a string variable containing time in hh:mm:ss format. How to convert it into time_t type? eg: string time_details = "16:35:12"
我有一个包含hh:mm:ss 格式时间的字符串变量。如何将其转换为 time_t 类型？例如：字符串 time_details = "16:35:12"
Also, how to compare two variables containing time so as to decide which is the earliest? eg : string curr_time = "18:35:21" string user_time = "22:45:31"
另外，如何比较两个包含时间的变量以确定哪个是最早的？例如：string curr_time = "18:35:21" string user_time = "22:45:31"
回答by v2blz
With C++11 you can now do
使用 C++11，您现在可以做到
struct std::tm tm;
std::istringstream ss("16:35:12");
ss >> std::get_time(&tm, "%H:%M:%S"); // or just %T in this case
std::time_t time = mktime(&tm);
see std::get_timeand strftimefor reference
请参阅std::get_time和strftime以供参考
回答by Adam Rosenfield
You can use strptime(3)to parse the time, and then mktime(3)to convert it to a time_t:
您可以使用strptime(3)来解析时间，然后mktime(3)将其转换为time_t：
const char *time_details = "16:35:12";
struct tm tm;
strptime(time_details, "%H:%M:%S", &tm);
time_t t = mktime(&tm); // t is now your desired time_t
回答by Mahmoud Al-Qudsi
This should work:
这应该有效：
int hh, mm, ss;
struct tm when = {0};
sscanf_s(date, "%d:%d:%d", &hh, &mm, &ss);
when.tm_hour = hh;
when.tm_min = mm;
when.tm_sec = ss;
time_t converted;
converted = mktime(&when);
Modify as needed.
根据需要进行修改。
