Android 设置 View 的 z 顺序使用 becomeChildToFront()
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setting z order of View with bringChildToFront()
提问by rob
I'm trying to set the z order of a UI element (i.e. a View) so that it will overlap another element, but calling ViewGroup.bringChildToFront() has a weird side effect....it moves the element to be the last item in the parent (the ViewGroup). Is this a bug, expected behavior, or what? More importantly, how can I set the z order or a View without this unfortunate side effect?
我正在尝试设置 UI 元素（即视图）的 z 顺序，以便它会与另一个元素重叠，但是调用 ViewGroup.bringChildToFront() 有一个奇怪的副作用......它将元素移动到最后一个父项（ViewGroup）中的项。这是错误，预期行为还是什么？更重要的是，如何设置 z 顺序或视图而不会有这种不幸的副作用？
回答by Romain Guy
This is the expected behavior. bringChildToFront() just changes the index of the View inside its parent.
这是预期的行为。BringChildToFront() 只是更改其父视图内的视图索引。
回答by Kumar
To send a view all the way back, do this:
要一直发送视图，请执行以下操作：
private void moveToBack(View currentView) {
ViewGroup viewGroup = ((ViewGroup) currentView.getParent());
int index = viewGroup.indexOfChild(currentView);
for(int i = 0; i<index; i++) {
viewGroup.bringChildToFront(viewGroup.getChildAt(i));
}
}
回答by sm abbas
bringChildToFront(child)does nothing but changes the index value of the child.
bringChildToFront(child)除了改变孩子的索引值之外什么都不做。
In order to bring a child to the front without using showNext()or showprevious(),
为了在不使用showNext()或的情况下将孩子带到前面showprevious()，
use
用
setDisplayedChild()and indexOfChild()together.
setDisplayedChild()并indexOfChild()在一起。
example
例子
vf.setDisplayedChild(vf.indexOfChild(child));
vf.setDisplayedChild(vf.indexOfChild(child));
where childis the viewthat needs to be brought front.
其中child是需要放在前面的视图。
Thanks
谢谢
