Python 类型错误:必须是字符串或缓冲区,而不是整数

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时间:2020-08-18 22:08:43  来源:igfitidea点击:

TypeError: must be string or buffer, not int

pythoncryptographyrainbowtable

提问by ajknzhol

i am trying to solve the Rainbow Tablesissue with password encryption and have come only this far.

我正在尝试Rainbow Tables使用密码加密来解决这个问题,并且仅到此为止。

import sys
import random
import hashlib

def mt_rand (low = 0, high = sys.maxint):
    """Generate a better random value
    """
    return random.randint (low, high)

def substr (s, start, length = None):
    """Returns the portion of string specified by the start and length
    parameters.
    """
    if len(s) >= start:
        return False
    if not length:
        return s[start:]
    elif length > 0:
        return s[start:start + length]
    else:
        return s[start:length]

def unique_salt():
    return substr(hashlib.sha1(mt_rand()),0,22)

password = "12345"
salt = unique_salt()
hash = hashlib.sha1(salt + password).hexdigest()
print(hash)

I am getting this error:

我收到此错误:

Traceback (most recent call last):
  File "C:/Users/Ajay/PycharmProjects/itertools/test.py", line 27, in <module>
    salt = unique_salt()
  File "C:/Users/Ajay/PycharmProjects/itertools/test.py", line 24, in unique_salt
    return substr(hashlib.sha1(mt_rand()),0,22)
TypeError: must be string or buffer, not int

I know i am missing something very trivial but cant get where i am missing. Please Help.

我知道我错过了一些非常微不足道的东西,但无法找到我错过的地方。请帮忙。

采纳答案by falsetru

hashlib.sha1accepts a string as a parameter.

hashlib.sha1接受一个字符串作为参数。

>>> import hashlib
>>> hashlib.sha1('asdf')
<sha1 HASH object @ 0000000002B97DF0>

But you're passing a int object. (The return value of the random.randintis intobject as the name suggest)

但是您正在传递一个 int 对象。(顾名思义random.randint就是int对象的返回值)

>>> hashlib.sha1(1234)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: must be string or buffer, not int

You can use os.urandomto generate random string:

您可以使用os.urandom生成随机字符串:

>>> import os
>>> hashlib.sha1(os.urandom(10)) # `os.urandom(10)` generate 10-bytes random string.
<sha1 HASH object @ 0000000002B97F30>
>>> hashlib.sha1(os.urandom(10)).digest()
'\x0c.y\x08\x13\xf0\x16.\xea\x05\x03\x07{6H\xa0U\xfe\xdfT'
>>> hashlib.sha1(os.urandom(10)).hexdigest()
'6e33d9cfdbd7ffcf062ee502eaa25893f618fcff'

回答by Madison May

You can use python's built-in function typeto inspect objects.

您可以使用 python 的内置函数type来检查对象。

>>>type(mt_rand())
int
>>>hashlib.sha1(mt_rand())
TypeError: must be string or buffer, not int

This is to be expected. Pass hashlib.sha1 a string instead.

这是可以预料的。将 hashlib.sha1 传递给一个字符串。

>>>hashlib.sha1("password")
<sha1 HASH object @ 0x1c89cb0>

回答by aIKid

hashlib.sha1needs a string to be hashed, but you put an integer.

hashlib.sha1需要一个字符串进行散列,但你输入了一个整数。

Convert it to string first:

首先将其转换为字符串:

def unique_salt():
    return substr(hashlib.sha1(str(mt_rand())),0,22)

Here's a bit of demo:

这是一个演示:

>>> import hashlib
>>> import random
>>> s = random.randint(1, 1000)
>>> hashlib.sha1(str(s)).digest()
'\xd1\x84\x01\xb1\xbb7\xc5\xd9)|\xf1o\xc48X\xb4\xfd\xb3x%'