JavaScript 中不区分大小写的正则表达式
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Case insensitive regex in JavaScript
提问by Amit
I want to extract a query string from my URL using JavaScript, and I want to do a case insensitive comparison for the query string name. Here is what I am doing:
我想使用 JavaScript 从我的 URL 中提取查询字符串，并且我想对查询字符串名称进行不区分大小写的比较。这是我在做什么：
var results = new RegExp('[\?&]' + name + '=([^&#]*)').exec(window.location.href);
if (!results) { return 0; }
return results[1] || 0;
But the above code does a case sensitive search. I tried /<regex>/ibut it did not help. Any idea how can that be achieved?
但是上面的代码做了区分大小写的搜索。我试过了，/<regex>/i但没有帮助。知道如何实现吗？
回答by Micha? Niklas
You can add 'i' modifier that means "ignore case"
您可以添加“i”修饰符，表示“忽略大小写”
var results = new RegExp('[\?&]' + name + '=([^&#]*)', 'i').exec(window.location.href);
回答by Brad Mace
modifiers are given as the second parameter:
修饰符作为第二个参数给出：
new RegExp('[\?&]' + name + '=([^&#]*)', "i")
回答by Diego Fortes
Simple one liner. In the example below it replaces every vowel with an X.
简单的一个班轮。在下面的示例中，它将每个元音替换为 X。
function replaceWithRegex(str, regex, replaceWith) {
return str.replace(regex, replaceWith);
}
replaceWithRegex('HEllo there', /[aeiou]/gi, 'X'); //"HXllX thXrX"
