.net 如何在 RestSharp 中向请求正文添加文本
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原文地址: http://stackoverflow.com/questions/5095692/
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How to add text to request body in RestSharp
提问by Matt G.
I'm trying to use RestSharp to consume a web service. So far everything's gone very well (cheers to John Sheehan and all contributors!) but I've run into a snag. Say I want to insert XML into the body of my RestRequest in its already serialized form (i.e., as a string). Is there an easy way to do this? It appears the .AddBody() function conducts serialization behinds the scenes, so my string is being turned into <String />.
我正在尝试使用 RestSharp 来使用 Web 服务。到目前为止，一切都进展顺利（为 John Sheehan 和所有贡献者干杯！）但我遇到了一个障碍。假设我想以已经序列化的形式（即，作为字符串）将 XML 插入到我的 RestRequest 的正文中。是否有捷径可寻？看来 .AddBody() 函数在幕后进行序列化，所以我的字符串正在变成<String />.
Any help is greatly appreciated!
任何帮助是极大的赞赏！
EDIT: A sample of my current code was requested. See below --
编辑：要求提供我当前代码的示例。见下文 -
private T ExecuteRequest<T>(string resource,
RestSharp.Method httpMethod,
IEnumerable<Parameter> parameters = null,
string body = null) where T : new()
{
RestClient client = new RestClient(this.BaseURL);
RestRequest req = new RestRequest(resource, httpMethod);
// Add all parameters (and body, if applicable) to the request
req.AddParameter("api_key", this.APIKey);
if (parameters != null)
{
foreach (Parameter p in parameters) req.AddParameter(p);
}
if (!string.IsNullOrEmpty(body)) req.AddBody(body); // <-- ISSUE HERE
RestResponse<T> resp = client.Execute<T>(req);
return resp.Data;
}
回答by dmitreyg
Here is how to add plain xml string to the request body:
以下是如何将纯 xml 字符串添加到请求正文：
req.AddParameter("text/xml", body, ParameterType.RequestBody);
req.AddParameter("text/xml", body, ParameterType.RequestBody);
回答by interesting-name-here
To Add to @dmitreyg's answer and per @jrahhali's comment to his answer, in the current version, as of the time this is posted it is v105.2.3, the syntax is as follows:
要添加到@dmitreyg 的答案以及根据@jrahhali 对其答案的评论，在当前版本中，截至发布时v105.2.3，语法如下：
request.Parameters.Add(new Parameter() {
ContentType = "application/json",
Name = "JSONPAYLOAD", // not required
Type = ParameterType.RequestBody,
Value = jsonBody
});
request.Parameters.Add(new Parameter() {
ContentType = "text/xml",
Name = "XMLPAYLOAD", // not required
Type = ParameterType.RequestBody,
Value = xmlBody
});
