C++：const char * 到 stringstream
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C++: const char * to stringstream
提问by user459811
Is it possible to put a const char* into a string stream?
是否可以将 const char* 放入字符串流中？
I think it's possible with the write() function in stringstream but I'm having trouble figuring out how to get the streamsize if i only know of the const char *.
我认为 stringstream 中的 write() 函数是可能的，但是如果我只知道 const char * ，我就无法弄清楚如何获得流大小。
Assuming size is my const char * variable:
假设大小是我的 const char * 变量：
stringstream s;
s.write(temp,size);
How do I get size? Thanks.
我如何获得尺寸？谢谢。
回答by fpointbin
I tested it, and it works correctly...
我测试过，它工作正常......
#include <iostream>
#include <sstream>
using namespace std;
int main()
{
stringstream s;
const char* token = "HELLO";
s << token;
cout << s.str() << endl;
return 0;
}
[facu@arch ~]$ g++ p.cpp
[facu@arch ~]$ ./a.out
HELLO
回答by dappawit
I may not be understanding correctly, but I think you're asking how to get the size of a char*string. To do that, all you need is strlen(str)which is in the <cstring>header. The string must be null terminated, though.
我可能没有正确理解，但我认为您是在问如何获取char*字符串的大小。要做到这一点，你需要的是strlen(str)这是在<cstring>报头。但是，该字符串必须以空字符结尾。
回答by fpointbin
I don't know if it is the best way to answer your question, but see:
我不知道这是否是回答您问题的最佳方式，但请参阅：
std::string _getline_ ( const char *str, const unsigned int ui_size )
{
std::string tmp;
unsigned short int flag = 0;
while ( flag < 2 )
{
if( *str != '##代码##' )
{
tmp.push_back( *str );
flag = 0;
}
else
{
tmp.push_back( ' ' );
flag++;
}
str++;
}
return tmp;
}
The problem is that "flag" will store two of "\0" no more... I don't know what is your proposite.. But i hope it will be useful for you... Maybe someone wanna fix it...
问题是“flag”将不再存储两个“\0”......我不知道你的提议是什么......但我希望它对你有用......也许有人想修复它...... .
