bash 替换所有文件中的字符串 - Unix
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Replace a string in all files - Unix
提问by alvas
I am trying to replace a string :::with ::for all lines in a batch of txtfiles (it can be considered as a word since there's always a space in front and behind it.
我试图替换字符串:::与::批处理中txtfiles的所有线路（也可以，因为总是有一个在前面和后面的空间被认为是一个单词。
I can do it with python like below, but is there a less 'over-kill' / convoluted way of doing this through the unix terminal?(Many pipes allowed)
我可以像下面这样使用 python 来完成，但是通过 unix 终端是否有更少的“过度杀伤”/复杂的方式来做到这一点？（允许多管）
indir = "./td/"
outdir = './od/'
for infile in glob.glob(os.path.join(indir,"*")):
_,FILENAME = os.path.split()
for l in codecs.open(infile,'r','utf8').readlines():
l = l.replace(":::","::").strip()
outfile = codecs.open(os.path.join(outdir,FILENAME),'a+','utf8')
print>>outfile, l
Then i move all files from od to td mv ./od/* ./td/*
然后我将所有文件从 od 移动到 td mv ./od/* ./td/*
回答by Beta
find . -name "./td/*.c" -exec sed -i "s/:::/::/g" '{}' \;
No need for od/at all.
od/根本不需要。
EDIT:
编辑：
A slightly simpler variation:
一个稍微简单的变体：
ls td/*.c | xargs sed -i '' "s/:::/::/g"
回答by chepner
A simple loop to process each file with sedshould suffice.
一个简单的循环来处理每个文件sed就足够了。
for inp in ./td/*; do
fname=${inp##*/}
sed 's/:::/::/g' "$inp" > ./od/"$fname"
done
