Java 无法获取 org.hibernate.persister.entity.SingleTableEntityPersister 的构造函数
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Could not get constructor for org.hibernate.persister.entity.SingleTableEntityPersister
提问by Stephen
I am actually new to hibernate and tried to set up 2 classes. Account and Person. Now all i try to do is create a one to one bidirectional dependency using annotations. Here are some details and code snippets:
我实际上是 hibernate 的新手，并尝试设置 2 个类。帐户和人员。现在我要做的就是使用注释创建一对一的双向依赖关系。以下是一些细节和代码片段：
Here are my libraries which i added to the build path, maybe i missed anything:
这是我添加到构建路径中的库，也许我错过了任何东西：
Account:
帐户：
package backend;
import java.util.Random;
import java.util.Collection;
import java.util.TreeSet;
import javax.persistence.*;
@Entity
@Table(name = "Account")
public class Account {
public static Random rnd = new Random();
private int id;
private String username;
private long password;
private long salt;
private Person person;
private String role;
private Collection<Account> friendlist;
public Account() {
}
public Account(String username, long password, Person person, String role) {
super();
this.username = username;
this.password = password;
this.setSalt();
this.person = person;
this.role = role;
this.friendlist = new TreeSet<Account>();
}
@Id
@GeneratedValue
@Column(name = "Id")
public int getId() {
return id;
}
public void setId(int id) {
this.id = id;
}
@Column(name = "Username")
public String getUsername() {
return username;
}
public void setUsername(String username) {
this.username = username;
}
@Column(name = "Password")
public long getPassword() {
return password;
}
public void setPassword(String password) {
this.password = (long) salt + password.hashCode();
}
@Column(name = "Salt")
public long getSalt() {
return salt;
}
public void setSalt() {
this.salt = rnd.nextLong();
if (this.salt < 0) {
this.salt = this.salt * (-1);
}
}
@OneToOne(cascade = CascadeType.ALL)
@JoinColumn(name = "Person_FK")
public Person getPerson() {
return person;
}
public void setPerson(Person person) {
this.person = person;
}
@Column(name = "Role")
public String getRole() {
return role;
}
public void setRole(String role) {
}
Person:
人：
package backend;
import javax.persistence.*;
@Entity
@Table(name ="Person")
public class Person {
private int id;
private String firstName;
private String lastName;
private String street;
private int houseNumber;
private String tel;
private String email;
private String mobile;
private Account account;
public Person() {
}
public Person(int id, String firstName, String lastName, String street,
int houseNumber, String tel, String email, String mobile,
Account account) {
super();
this.id= id;
this.firstName = firstName;
this.lastName = lastName;
this.street = street;
this.houseNumber = houseNumber;
this.tel = tel;
this.email = email;
this.mobile = mobile;
this.account = account;
}
@Id
@GeneratedValue
@Column(name="Id")
public int getId() {
return id;
}
public void setId(int id) {
this.id = id;
}
@Column(name="Firstname")
public String getFirstName() {
return firstName;
}
public void setFirstName(String firstName) {
this.firstName = firstName;
}
@Column(name="Lastname")
public String getLastName() {
return lastName;
}
public void setLastName(String lastName) {
this.lastName = lastName;
}
@Column(name="Street")
public String getStreet() {
return street;
}
public void setStreet(String street) {
this.street = street;
}
@Column(name="Housenumber")
public int getHouseNumber() {
return houseNumber;
}
public void setHouseNumber(int houseNumber) {
this.houseNumber = houseNumber;
}
@Column(name="Tel")
public String getTel() {
return tel;
}
public void setTel(String tel) {
this.tel = tel;
}
@Column(name="Email")
public String getEmail() {
return email;
}
public void setEmail(String email) {
this.email = email;
}
@Column(name="Mobile")
public String getMobile() {
return mobile;
}
public void setMobile(String mobile) {
this.mobile = mobile;
}
@OneToOne(mappedBy = "person", cascade = CascadeType.ALL)
public Account getAccount() {
return account;
}
public void setAccount(Account account) {
this.account = account;
}
}
Hibernate cfg xml:
休眠 cfg xml：
<?xml version='1.0' encoding='utf-8'?>
<!DOCTYPE hibernate-configuration PUBLIC
"-//Hibernate/Hibernate Configuration DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd">
<hibernate-configuration>
<session-factory>
<!-- Alternative 1: MySQL -->
<!-- Database connection settings: MySQL -->
<property name="connection.driver_class">com.mysql.jdbc.Driver</property>
<property name="connection.url">jdbc:mysql:///chat.application.db</property>
<property name="connection.username">root</property>
<property name="connection.password"></property>
<property name="dialect">org.hibernate.dialect.MySQLDialect</property>
<!-- JDBC connection pool (use the built-in) -->
<property name="connection.pool_size">1</property>
<!-- Enable Hibernate's automatic session context management -->
<property name="current_session_context_class">thread</property>
<!-- Disable the second-level cache -->
<property name="cache.provider_class">org.hibernate.cache.NoCacheProvider</property>
<!-- Echo all executed SQL to stdout -->
<property name="show_sql">true</property>
<property name="format_sql">true</property>
<!-- Drop and re-create the database schema on startup -->
<property name="hbm2ddl.auto">create</property>
<property name="hibernate.format_sql">true</property>
<!-- Auflistung der gemappten Klassen (Package + Class-Name) -->
<mapping class="backend.Account"/>
<mapping class="backend.Person"/>
<!-- <mapping class="backend.Role"/> -->
</session-factory>
</hibernate-configuration>
And here is my problem. when i try to start a simple main class creating some objects and saving them, just to test, i get this:
这是我的问题。当我尝试启动一个简单的主类来创建一些对象并保存它们时，只是为了测试，我得到了这个：
( %%%% Error Creating SessionFactory %%%% = result of my try-catch before printStackTrace)
（ %%%% 错误创建 SessionFactory %%%% = 我在 printStackTrace 之前尝试捕获的结果）
INFO: HHH000397: Using ASTQueryTranslatorFactory
%%%% Error Creating SessionFactory %%%%
org.hibernate.MappingException: Could not get constructor for org.hibernate.persister.entity.SingleTableEntityPersister
at org.hibernate.persister.internal.PersisterFactoryImpl.create(PersisterFactoryImpl.java:185)
at org.hibernate.persister.internal.PersisterFactoryImpl.createEntityPersister(PersisterFactoryImpl.java:135)
at org.hibernate.internal.SessionFactoryImpl.<init>(SessionFactoryImpl.java:385)
at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1769)
at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1840)
at backend.HibernateSessionFactory.currentSession(HibernateSessionFactory.java:21)
at backend.HibernateSessionFactory.getCfg(HibernateSessionFactory.java:48)
at backend.Main.main(Main.java:14)
Caused by: org.hibernate.HibernateException: Unable to instantiate default tuplizer [org.hibernate.tuple.entity.PojoEntityTuplizer]
at org.hibernate.tuple.entity.EntityTuplizerFactory.constructTuplizer(EntityTuplizerFactory.java:138)
at org.hibernate.tuple.entity.EntityTuplizerFactory.constructDefaultTuplizer(EntityTuplizerFactory.java:188)
at org.hibernate.tuple.entity.EntityMetamodel.<init>(EntityMetamodel.java:341)
at org.hibernate.persister.entity.AbstractEntityPersister.<init>(AbstractEntityPersister.java:507)
at org.hibernate.persister.entity.SingleTableEntityPersister.<init>(SingleTableEntityPersister.java:146)
at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method)
at sun.reflect.NativeConstructorAccessorImpl.newInstance(Unknown Source)
at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(Unknown Source)
at java.lang.reflect.Constructor.newInstance(Unknown Source)
at org.hibernate.persister.internal.PersisterFactoryImpl.create(PersisterFactoryImpl.java:163)
... 7 more
Caused by: java.lang.reflect.InvocationTargetException
at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method)
at sun.reflect.NativeConstructorAccessorImpl.newInstance(Unknown Source)
at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(Unknown Source)
at java.lang.reflect.Constructor.newInstance(Unknown Source)
at org.hibernate.tuple.entity.EntityTuplizerFactory.constructTuplizer(EntityTuplizerFactory.java:135)
... 16 more
Caused by: org.hibernate.PropertyNotFoundException: Could not find a setter for property salt in class backend.Account
at org.hibernate.property.BasicPropertyAccessor.createSetter(BasicPropertyAccessor.java:252)
at org.hibernate.property.BasicPropertyAccessor.getSetter(BasicPropertyAccessor.java:245)
at org.hibernate.mapping.Property.getSetter(Property.java:326)
at org.hibernate.tuple.entity.PojoEntityTuplizer.buildPropertySetter(PojoEntityTuplizer.java:444)
at org.hibernate.tuple.entity.AbstractEntityTuplizer.<init>(AbstractEntityTuplizer.java:201)
at org.hibernate.tuple.entity.PojoEntityTuplizer.<init>(PojoEntityTuplizer.java:82)
... 21 more
Exception in thread "main" java.lang.NullPointerException
at backend.HibernateSessionFactory.currentSession(HibernateSessionFactory.java:28)
at backend.HibernateSessionFactory.getCfg(HibernateSessionFactory.java:48)
at backend.Main.main(Main.java:14)
So i really dont know how to handle this exception. I tried to google it and such but all i found out is that some people had spelling mistakes in their code and this was the reason for it. but unfortunately i dont have spellies in my code. Can someone help me? I will be happy to also post my SessionFactoryCode or the main class if neccessary. Due to the fact that i am new to hibernate i take every advise =)
所以我真的不知道如何处理这个异常。我试图用谷歌搜索它，但我发现有些人在他们的代码中有拼写错误，这就是原因。但不幸的是，我的代码中没有拼写。有人能帮我吗？如果需要，我也很乐意发布我的 SessionFactoryCode 或主类。由于我是 hibernate 的新手，我接受了每一个建议 =)
BTW: SQL DB is running via XAMPP.
顺便说一句：SQL DB 通过 XAMPP 运行。
Thanks.
谢谢。
回答by harrybvp
You are missing setter for saltproperty as indicated by the exception
salt如异常所示，您缺少属性的setter
Please add the setter as
请将设置器添加为
public void setSalt(long salt) {
this.salt=salt;
}
回答by Augusto
If you look at the chain of exceptions, the problem is
如果您查看异常链，问题是
Caused by: org.hibernate.PropertyNotFoundException: Could not find a setter for property salt in class backend.Account
引起：org.hibernate.PropertyNotFoundException：在类 backend.Account 中找不到属性盐的设置器
The problem is that the method Account.setSalt() works fine when you create an instance but not when you retrieve an instance from the database. This is because you don't want to create a new salt each time you load an Account.
问题是 Account.setSalt() 方法在您创建实例时工作正常，但在您从数据库中检索实例时却没有。这是因为您不想每次加载帐户时都创建一个新的盐。
To fix this, create a method setSalt(long) with visibility private and Hibernate will be able to set the value (just a note, I think it works with Private, but you might need to make it package or protected).
要解决此问题，请创建一个具有私有可见性的方法 setSalt(long)，Hibernate 将能够设置该值（只是一个说明，我认为它适用于 Private，但您可能需要将其打包或受保护）。
回答by Vaibhav Jain
In my case the problem was because of conflicting Jars.
在我的情况下，问题是因为 Jars 冲突。
Here is the full list of jars which is working absolutely fine for me.
这是 jars 的完整列表，对我来说非常好。
antlr-2.7.7.jar
byte-buddy-1.8.12.jar
c3p0-0.9.5.2.jar
classmate-1.3.4.jar
dom4j-1.6.1.jar
geolatte-geom-1.3.0.jar
hibernate-c3p0-5.3.1.Final.jar
hibernate-commons-annotations-5.0.3.Final.jar
hibernate-core-5.3.1.Final.jar
hibernate-envers-5.3.1.Final.jar
hibernate-jpamodelgen-5.3.1.Final.jar
hibernate-osgi-5.3.1.Final.jar
hibernate-proxool-5.3.1.Final.jar
hibernate-spatial-5.3.1.Final.jar
jandex-2.0.3.Final.jar
javassist-3.22.0-GA.jar
javax.interceptor-api-1.2.jar
javax.persistence-api-2.2.jar
jboss-logging-3.3.2.Final.jar
jboss-transaction-api_1.2_spec-1.1.1.Final.jar
jts-core-1.14.0.jar
mchange-commons-java-0.2.11.jar
mysql-connector-java-5.1.21.jar
org.osgi.compendium-4.3.1.jar
org.osgi.core-4.3.1.jar
postgresql-42.2.2.jar
proxool-0.8.3.jar
slf4j-api-1.6.1.jar
回答by Stephen Paul
I encountered this error when upgrading from jdk10 to jdk11. Adding the following dependency fixed the problem:
从jdk10升级到jdk11时遇到这个错误。添加以下依赖项解决了问题：
<dependency>
<groupId>org.javassist</groupId>
<artifactId>javassist</artifactId>
<version>3.25.0-GA</version>
</dependency>
回答by Mina Shirali
in my case, the problem got solved only by implementing serializableas below:
就我而言，只有通过如下实现可序列化才能解决问题：
@Entity @Table(name = "User" , uniqueConstraints = { @UniqueConstraint(columnNames = {"nam"}) }) public class User extends GenericT implements Serializable
@Entity @Table(name = "User" , uniqueConstraints = { @UniqueConstraint(columnNames = {"nam"}) }) 公共类 User extends GenericT 实现了可序列化
回答by Praveesh P
I resolved this issue by excluding byte-buddy dependency from springfox
我通过从 springfox 中排除字节伙伴依赖解决了这个问题
<dependency>
<groupId>io.springfox</groupId>
<artifactId>springfox-swagger2</artifactId>
<version>2.7.0</version>
<exclusions>
<exclusion>
<groupId>net.bytebuddy</groupId>
<artifactId>byte-buddy</artifactId>
</exclusion>
</exclusions>
</dependency>
<dependency>
<groupId>io.springfox</groupId>
<artifactId>springfox-swagger-ui</artifactId>
<version>2.7.0</version>
<exclusions>
<exclusion>
<groupId>net.bytebuddy</groupId>
<artifactId>byte-buddy</artifactId>
</exclusion>
</exclusions>
</dependency>
