ios Xcode 5 和资产目录:如何引用 LaunchImage?

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时间:2020-08-31 01:54:04  来源:igfitidea点击:

Xcode 5 & Asset Catalog: How to reference the LaunchImage?

iosxcodeios7xcode5asset-catalog

提问by toblerpwn

I am using Xcode 5's Asset Catalog, and I would like to use my LaunchImageas the background image of my home view (a pretty common practice to make the transition from 'loading' to 'loaded' look smooth).

我正在使用 Xcode 5 的资产目录,我想使用我的LaunchImage作为我的主视图的背景图像(一种非常常见的做法,使从“加载”到“加载”的过渡看起来很平滑)。

I would like to use the same entry in the Asset Catalog to save space and not have to replicate the image in two different Image Sets.

我想在资产目录中使用相同的条目来节省空间,而不必在两个不同的图像集中复制图像。

However, calling:

但是,调用:

UIImage *image = [UIImage imageNamed:@"LaunchImage"]; //returns nil

回答by Pichirichi

This is the (almost) complete list of the LaunchImage (excluding the iPad images with no status bar):

这是 LaunchImage 的(几乎)完整列表(不包括没有状态栏的 iPad 图像):

回答by Cherpak Evgeny

- (NSString *)splashImageNameForOrientation:(UIInterfaceOrientation)orientation {
    CGSize viewSize = self.view.bounds.size;
    NSString* viewOrientation = @"Portrait";
    if (UIDeviceOrientationIsLandscape(orientation)) {
        viewSize = CGSizeMake(viewSize.height, viewSize.width);
        viewOrientation = @"Landscape";
    }

    NSArray* imagesDict = [[[NSBundle mainBundle] infoDictionary] valueForKey:@"UILaunchImages"];
    for (NSDictionary* dict in imagesDict) {
        CGSize imageSize = CGSizeFromString(dict[@"UILaunchImageSize"]);
        if (CGSizeEqualToSize(imageSize, viewSize) && [viewOrientation isEqualToString:dict[@"UILaunchImageOrientation"]])
            return dict[@"UILaunchImageName"];
    }
    return nil;
}

回答by JosephH

The LaunchImages are special, and aren't actually an asset catalog on the device. If you look using iFunBox/iExplorer/etc (or on the simulator, or in the build directory) you can see the final names, and then write code to use them - eg. for an iOS7-only iPhone-only project, this will set the right launch image:

LaunchImages 很特别,实际上并不是设备上的资产目录。如果您查看使用 iFunBox/iExplorer/etc(或在模拟器上,或在构建目录中),您可以看到最终名称,然后编写代码来使用它们 - 例如。对于仅限 iOS7 的仅限 iPhone 的项目,这将设置正确的启动图像:

NSString *launchImage;
if  ((UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone) &&
     ([UIScreen mainScreen].bounds.size.height > 480.0f)) {
    launchImage = @"LaunchImage-700-568h";
} else {
    launchImage = @"LaunchImage-700";
}

[self.launchImageView setImage:[UIImage imageNamed:launchImage]];

I put this into viewDidLoad.

我把它放到 viewDidLoad 中。

This isn't really ideal, it would be great if Apple would give us a nice API to do this.

这不是很理想,如果 Apple 能给我们一个很好的 API 来做到这一点,那就太好了。

回答by nonamelive

My app currently only supports iOS 7 and later.

我的应用目前仅支持 iOS 7 及更高版本。

This is how I reference the launch image from the asset catalog:

这是我从资产目录中引用启动图像的方式:

NSDictionary *dict = @{@"320x480" : @"LaunchImage-700",
                       @"320x568" : @"LaunchImage-700-568h",
                       @"375x667" : @"LaunchImage-800-667h",
                       @"414x736" : @"LaunchImage-800-Portrait-736h"};
NSString *key = [NSString stringWithFormat:@"%dx%d",
    (int)[UIScreen mainScreen].bounds.size.width,
    (int)[UIScreen mainScreen].bounds.size.height];
UIImage *launchImage = [UIImage imageNamed:dict[key]];

You can add more key value pairs if you want to support older iOS versions.

如果您想支持较旧的 iOS 版本,您可以添加更多键值对。

回答by vilanovi

Here a category on UIImage based on the solution provided by Cherpak Evgeny above.

这里是基于上面 Cherpak Evgeny 提供的解决方案的 UIImage 类别。

UIImage+SplashImage.h:

UIImage+SplashImage.h:

#import <UIKit/UIKit.h>

/**
 * Category on `UIImage` to access the splash image.
 **/
@interface UIImage (SplashImage)

/**
 * Return the name of the splash image for a given orientation.
 * @param orientation The interface orientation.
 * @return The name of the splash image.
 **/
+ (NSString *)si_splashImageNameForOrientation:(UIInterfaceOrientation)orientation;

/**
 * Returns the splash image for a given orientation.
 * @param orientation The interface orientation.
 * @return The splash image.
 **/
+ (UIImage*)si_splashImageForOrientation:(UIInterfaceOrientation)orientation;

@end

UIImage+SplashImage.m:

UIImage+SplashImage.m:

#import "UIImage+SplashImage.h"

@implementation UIImage (SplashImage)

+ (NSString *)si_splashImageNameForOrientation:(UIInterfaceOrientation)orientation
{
    CGSize viewSize = [UIScreen mainScreen].bounds.size;

    NSString *viewOrientation = @"Portrait";

    if (UIDeviceOrientationIsLandscape(orientation))
    {
        viewSize = CGSizeMake(viewSize.height, viewSize.width);
        viewOrientation = @"Landscape";
    }

    NSArray* imagesDict = [[[NSBundle mainBundle] infoDictionary] valueForKey:@"UILaunchImages"];

    for (NSDictionary *dict in imagesDict)
    {
        CGSize imageSize = CGSizeFromString(dict[@"UILaunchImageSize"]);
        if (CGSizeEqualToSize(imageSize, viewSize) && [viewOrientation isEqualToString:dict[@"UILaunchImageOrientation"]])
            return dict[@"UILaunchImageName"];
    }
    return nil;
}

+ (UIImage*)si_splashImageForOrientation:(UIInterfaceOrientation)orientation
{
    NSString *imageName = [self si_splashImageNameForOrientation:orientation];
    UIImage *image = [UIImage imageNamed:imageName];
    return image;
}

@end

回答by Anthony Scott

@codeman's answer updated for Swift 1.2:

@codeman 为 Swift 1.2 更新了答案:

func splashImageForOrientation(orientation: UIInterfaceOrientation, size: CGSize) -> String? {
    var viewSize        = size
    var viewOrientation = "Portrait"

    if UIInterfaceOrientationIsLandscape(orientation) {
        viewSize        = CGSizeMake(size.height, size.width)
        viewOrientation = "Landscape"
    }

    if let imagesDict = NSBundle.mainBundle().infoDictionary as? [String: AnyObject] {
        if let imagesArray = imagesDict["UILaunchImages"] as? [[String: String]] {
            for dict in imagesArray {
                if let sizeString = dict["UILaunchImageSize"], let imageOrientation = dict["UILaunchImageOrientation"] {
                    let imageSize = CGSizeFromString(sizeString)
                    if CGSizeEqualToSize(imageSize, viewSize) && viewOrientation == imageOrientation {
                        if let imageName = dict["UILaunchImageName"] {
                            return imageName
                        }
                    }
                }
            }
        }
    }

    return nil

}

To call it, and to support rotation for iOS 8:

调用它,并支持 iOS 8 的旋转:

override func viewWillAppear(animated: Bool) {
    if let img = splashImageForOrientation(UIApplication.sharedApplication().statusBarOrientation, size: self.view.bounds.size) {
        backgroundImage.image = UIImage(named: img)
    }
}

override func viewWillTransitionToSize(size: CGSize, withTransitionCoordinator coordinator: UIViewControllerTransitionCoordinator) {
    let orientation = size.height > size.width ? UIInterfaceOrientation.Portrait : UIInterfaceOrientation.LandscapeLeft

    if let img = splashImageForOrientation(orientation, size: size) {
        backgroundImage.image = UIImage(named: img)
    }

}

Just what I needed, thanks!

正是我需要的,谢谢!

回答by codeman

Swift version of Cherpak Evgeny's answer:

Cherpak Evgeny 答案的 Swift 版本:

    func splashImageForOrientation(orientation: UIInterfaceOrientation) -> String {
        var viewSize = self.view.bounds.size
        var viewOrientation = "Portrait"
        if UIInterfaceOrientationIsLandscape(orientation) {
           viewSize = CGSizeMake(viewSize.height, viewSize.width)
           viewOrientation = "Landscape"
        }
        let imagesDict = NSBundle.mainBundle().infoDictionary as Dictionary<NSObject,AnyObject>!
        let imagesArray = imagesDict["UILaunchImages"] as NSArray
        for dict in imagesArray {
            let dictNSDict = dict as NSDictionary
            let imageSize = CGSizeFromString(dictNSDict["UILaunchImageSize"] as String)
            if CGSizeEqualToSize(imageSize, viewSize) && viewOrientation == (dictNSDict["UILaunchImageOrientation"] as String) {
                return dictNSDict["UILaunchImageName"] as String
            }
        }
        return ""
    }

回答by zaheer

I just wrote a general method to get the splash image name for iPhone and iPad (Landscape, Portrait), It worked for me, Hope It helps you as well. I wrote this with help of other SO answers, thanks @Pichirichi for whole list.

我刚刚写了一个通用方法来获取 iPhone 和 iPad(横向、纵向)的初始图像名称,它对我有用,希望它也能帮助你。我在其他 SO 答案的帮助下写了这篇文章,感谢 @Pichirichi 提供整个列表。

+(NSString*)getLaunchImageName
{

 NSArray* images= @[@"LaunchImage.png", @"[email protected]",@"[email protected]",@"[email protected]",@"[email protected]",@"LaunchImage-700-Portrait@2x~ipad.png",@"LaunchImage-Portrait@2x~ipad.png",@"LaunchImage-700-Portrait~ipad.png",@"LaunchImage-Portrait~ipad.png",@"LaunchImage-Landscape@2x~ipad.png",@"LaunchImage-700-Landscape@2x~ipad.png",@"LaunchImage-Landscape~ipad.png",@"LaunchImage-700-Landscape~ipad.png"];

UIImage *splashImage;

if ([self isDeviceiPhone])
{
    if ([self isDeviceiPhone4] && [self isDeviceRetina])
    {
        splashImage = [UIImage imageNamed:images[1]];
        if (splashImage.size.width!=0)
            return images[1];
        else
            return images[2];
    }
    else if ([self isDeviceiPhone5])
    {
        splashImage = [UIImage imageNamed:images[1]];
        if (splashImage.size.width!=0)
            return images[3];
        else
            return images[4];
    }
    else
        return images[0]; //Non-retina iPhone
}
else if ([[UIDevice currentDevice] orientation]==UIDeviceOrientationPortrait || [[UIDevice currentDevice] orientation] == UIDeviceOrientationPortraitUpsideDown)//iPad Portrait
{
    if ([self isDeviceRetina])
    {
        splashImage = [UIImage imageNamed:images[5]];
        if (splashImage.size.width!=0)
            return images[5];
        else
            return images[6];
    }
    else
    {
        splashImage = [UIImage imageNamed:images[7]];
        if (splashImage.size.width!=0)
            return images[7];
        else
            return images[8];
    }

}
else
{
    if ([self isDeviceRetina])
    {
        splashImage = [UIImage imageNamed:images[9]];
        if (splashImage.size.width!=0)
            return images[9];
        else
            return images[10];
    }
    else
    {
        splashImage = [UIImage imageNamed:images[11]];
        if (splashImage.size.width!=0)
            return images[11];
        else
            return images[12];
    }
 }
}

Other utility methods are

其他实用方法是

+(BOOL)isDeviceiPhone
{
 if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone)
 {
     return TRUE;
 }

 return FALSE;
}

+(BOOL)isDeviceiPhone4
{
 if ([[UIScreen mainScreen] bounds].size.height==480)
    return TRUE;

 return FALSE;
}


+(BOOL)isDeviceRetina
{
 if ([[UIScreen mainScreen] respondsToSelector:@selector(displayLinkWithTarget:selector:)] &&
    ([UIScreen mainScreen].scale == 2.0))        // Retina display
 {
    return TRUE;
 } 
 else                                          // non-Retina display
 {
     return FALSE;
 }
}


+(BOOL)isDeviceiPhone5
{
 if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone && [[UIScreen mainScreen] bounds].size.height>480)
 {
    return TRUE;
 }
 return FALSE;
}

回答by Adam

Following @Pichirich's answer, I referenced my launchimage in InterfaceBuilder as:

按照@Pichirich 的回答,我在 InterfaceBuilder 中引用了我的启动图像:

"LaunchImage.png"

“启动图像.png”

...and with Xcode 5.0.2, it's automatically plucking the appropriate image straight out of the Asset Catalog.

...使用 Xcode 5.0.2,它会自动直接从资产目录中提取适当的图像。

This is what I'd expect - except for Apple's viciously nasty move of silently renaming "Default.png" to "LaunchImage.png" :)

这就是我所期望的 - 除了 Apple 将“Default.png”默默地重命名为“LaunchImage.png”的恶毒举动:)

回答by Vladimír Slavík

In the documentationthere is clearly stated:

文档中有明确的说明:

"Each set in an asset catalog has a name. You can use that nameto programmatically load any individual image contained in the set. To load an image, call the UIImage:ImageNamed:method, passing the name of the set that contains the image."

“资产目录中的每个集合都有一个名称您可以使用该名称以编程方式加载集合中包含的任何单个图像。要加载图像,请调用UIImage:ImageNamed:方法,传递包含图像的集合的名称.”

Using Pichirichi's list helps to solve this inconsistency.

使用 Pichirichi 的列表有助于解决这种不一致。