php domdocument 获取节点值，其中属性值是
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时间：2020-08-26 01:23:59 来源:igfitidea点击:
php domdocument get node value where attribute value is
提问by Frits
Say my XML looks like this:
假设我的 XML 如下所示：
<record>
<row name="title">this item</row>
<row name="url">this url</row>
</record>
Now I'm doing something like this:
现在我正在做这样的事情：
$xml = new DOMDocument();
$xml->load('xmlfile.xml');
echo $xml->getElementByTagName('row')->item(0)->attributes->getNamedItem('title')->nodeValue;
But this just gives me:
但这只是给了我：
NOTICE: Trying to get property of non-object id
注意：试图获取非对象 id 的属性
Does anybody know how to get the node value where the "name" attribute has value "title"?
有人知道如何获取“name”属性值为“title”的节点值吗？
回答by Yoshi
Try:
尝试：
$xml = new DOMDocument();
$xml->loadXml('
<record>
<row name="title">this item</row>
<row name="url">this url</row>
</record>
');
$xpath = new DomXpath($xml);
// traverse all results
foreach ($xpath->query('//row[@name="title"]') as $rowNode) {
echo $rowNode->nodeValue; // will be 'this item'
}
// Or access the first result directly
$rowNode = $xpath->query('//row[@name="title"][1]')->item(0);
if ($rowNode instanceof DomElement) {
echo $rowNode->nodeValue;
}
回答by Liam Bailey
foreach ($xml->getElementsByTagName('row') as $element)
{
if ($element->getAttribute('name') == "title")
{
echo $element->nodeValue;
}
}
回答by hashchange
$xpath = new DOMXPath( $xml );
$val = $xpath->query( '//row[@name="title"]' )->item(0)->nodeValue;
