Android 如何显示一个视图 3 秒，然后隐藏它？
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How to show a view for 3 seconds, and then hide it?
提问by Tom Brito
I tried with threads, but android throws "CalledFromWrongThreadException: Only the original thread that created a view hierarchy can touch its views.".
我尝试使用线程，但 android 抛出“CalledFromWrongThreadException：只有创建视图层次结构的原始线程才能触摸其视图。”。
So how can I wait 3 seconds and then hide the view, letting the GUI responsive?
那么我怎样才能等待 3 秒然后隐藏视图，让 GUI 响应呢？
--
——
A Timer uses another thread either, so it will not solve..
定时器也使用另一个线程，所以它不会解决..
采纳答案by Brandon O'Rourke
Spawn a separate thread that sleeps for 3 seconds then call runOnUiThreadto hide the view.
生成一个单独的线程，该线程休眠 3 秒，然后调用runOnUiThread以隐藏视图。
Thread thread = new Thread() {
@Override
public void run() {
try {
Thread.sleep(3000);
} catch (InterruptedException e) {
}
runOnUiThread(new Runnable() {
@Override
public void run() {
// Do some stuff
}
});
}
};
thread.start(); //start the thread
回答by user890973
There is an easier way to do it: use View.postDelayed(runnable, delay)
有一种更简单的方法：使用View.postDelayed(runnable, delay)
View view = yourView;
view.postDelayed(new Runnable() {
public void run() {
view.setVisibility(View.GONE);
}
}, 3000);
It's not very precise: may be hidden in 3.5 or 3.2 seconds, because it posts into the ui thread's message queue.
它不是很精确：可能会在 3.5 或 3.2 秒后隐藏，因为它会发布到 ui 线程的消息队列中。
Use post() or runOnUiThread() just something as setTimeout().
使用 post() 或 runOnUiThread() 就像 setTimeout() 一样。
回答by mbonnin
Without the need to have a reference to a view or sleep a thread:
无需引用视图或休眠线程：
new Handler().postDelayed(new Runnable() {
@Override
public void run() {
// do stuff
}
}, 3000);
回答by Gudin
I know this is a stretch, but here's an answer with coroutines if you happen to use them:
我知道这是一个延伸，但是如果您碰巧使用协程，这里有一个答案：
lifecycleScope.launch {
delay(3000)
header.visibility = View.GONE
}
