python 有谁知道一种打乱列表中元素的方法？
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Does anyone know a way to scramble the elements in a list?
提问by TIMEX
thelist = ['a','b','c','d']
How I can to scramble them in Python?
我怎样才能在 Python 中打乱它们？
回答by Peter
>>> import random
>>> thelist = ['a', 'b', 'c', 'd']
>>> random.shuffle(thelist)
>>> thelist
['d', 'a', 'c', 'b']
Your result will (hopefully!) vary.
您的结果会（希望如此！）有所不同。
回答by Phil
import random
random.shuffle(thelist)
Note, this shuffles the list in-place.
请注意，这会原地打乱列表。
回答by Greg Hewgill
回答by RichieHindle
Use the shufflefunction from the randommodule:
使用模块中的shuffle函数random：
>>> from random import shuffle
>>> thelist = ['a','b','c','d']
>>> shuffle(thelist)
>>> thelist
['c', 'a', 'b', 'd']
回答by Omar Cusma Fait
in-placeshuffle (modifies v, returns None)
就地洗牌（修改 v，返回 None）
random.shuffle(v)
not in-placeshuffle (if you don't want to modify the original array, creates a shuffled copy)
not in-placeshuffle（如果你不想修改原始数组，创建一个shuffled副本）
v = random.sample(v, len(v))
