正确使用 jQuery select2 的 initSelection 回调与远程数据
声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow
原文地址: http://stackoverflow.com/questions/15174635/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Proper usage of jQuery select2's initSelection callback with remote data
提问by balteo
I use jQuery select2 plugin in order to retrieve postcodes using the provided ajax callback function as follows:
我使用 jQuery select2 插件来使用提供的 ajax 回调函数检索邮政编码,如下所示:
$(document).ready(function() {
$("#postcodes").select2({
placeholder : "Search for a postcode",
multiple : true,
minimumInputLength : 3,
ajax : {
url : "/bignibou/utils/findGeolocationPostcodeByPostcodeStartingWith.json",
dataType : 'json',
data : function(term) {
return {
postcode : term
};
},
results : function(data) {
console.log(data);
return {
results : $.map(data, function(item) {
return {
id : item.id,
text : item.postcode
};
})
};
}
}
});
});
Once two postcodes are selected I get the resulting hidden input
in the DOM:
一旦选择了两个邮政编码,我就会hidden input
在 DOM 中得到结果:
<input type="hidden" class="bigdrop select2-offscreen" id="postcodes" style="width:600px" name="familyAdvertisement.postcodes" value="4797,4798" tabindex="-1">
The issue I have is that once the form is redisplayed (for instance in the event of some other controls being in error), the selections (i.e. the two postcodes and especially the text
) don't show in the form although the hidden input
does have the two values (i.e. 4797 and 4798, which are the id
s for the postcode).
我遇到的问题是,一旦重新显示表单(例如,在某些其他控件出错的情况下),选择(即两个邮政编码,尤其是text
)不会显示在表单中,尽管hidden input
确实有两个值(即 4797 和 4798,它们是id
邮政编码的s)。
I am not sure if I have to do another ajax round trip when the form is redisplayed or if there is a better way to go.
我不确定在重新显示表单时是否必须再进行一次 ajax 往返,或者是否有更好的方法。
Can anyone please advise?
任何人都可以请指教吗?
回答by Arun P Johny
The initSelection method has to pass the values which has to be present in the select2
initSelection 方法必须传递必须存在于 select2
Ex:
前任:
$("#postcodes").select2({
placeholder : "Search for a postcode",
multiple : true,
minimumInputLength : 1,
data:[],
initSelection : function (element, callback) {
var data = [{id:1,text:'bug'},{id:2,text:'duplicate'}];
callback(data);
}
}).select2('val', ['1', '2']);
Demo: Fiddle
演示:小提琴