java 正则表达式中的转义路径分隔符
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Escape path separator in a regular expression
提问by Guido
I need to write a regular expression that finds javascript files that match
我需要编写一个正则表达式来查找匹配的 javascript 文件
<anypath><slash>js<slash><anything>.js
For example, it should work for both :
例如，它应该适用于两个：
- c:\mysite\js\common.js (Windows)
- /var/www/mysite/js/common.js (UNIX)
- c:\mysite\js\common.js (Windows)
- /var/www/mysite/js/common.js (UNIX)
The problem is that the file separator in Windows is not being properly escaped :
问题是 Windows 中的文件分隔符没有正确转义：
pattern = Pattern.compile(
"^(.+?)" +
File.separator +
"js" +
File.separator +
"(.+?).js$" );
Throwing
投掷
java.util.regex.PatternSyntaxException: Illegal/unsupported escape sequence
Is there any way to use a common regular expression that works in both Windows and UNIX systems ?
有没有办法使用在 Windows 和 UNIX 系统中都可以使用的通用正则表达式？
回答by Tomalak
Does Pattern.quote(File.separator)do the trick?
有Pattern.quote(File.separator)技巧吗？
EDIT: This is available as of Java 1.5 or later. For 1.4, you need to simply escape the file separator char:
编辑：这在 Java 1.5 或更高版本中可用。对于 1.4，您需要简单地转义文件分隔符字符：
"\" + File.separator
Escaping punctuation characters will not break anything, but escaping letters or numbers unconditionally will either change them to their special meaning or lead to a PatternSyntaxException. (Thanks Alan Mfor pointing this out in the comments!)
转义标点符号不会破坏任何内容，但无条件转义字母或数字会将它们更改为它们的特殊含义或导致PatternSyntaxException。（感谢Alan M在评论中指出这一点！）
回答by Alan Moore
Is there any way to use a common regular expression that works in both Windows and UNIX systems ?
有没有办法使用在 Windows 和 UNIX 系统中都可以使用的通用正则表达式？
Yes, just use a regex that matches both kinds of separator.
是的，只需使用匹配两种分隔符的正则表达式即可。
pattern = Pattern.compile(
"^(.+?)" +
"[/\\]" +
"js" +
"[/\\]" +
"(.+?)\.js$" );
It's safe because neither Windows nor Unix permits those characters in a file or directory name.
这是安全的，因为 Windows 和 Unix 都不允许在文件或目录名称中使用这些字符。
回答by Peter van der Heijden
Can't you just use a backslash to escape the path separator like so:
您不能像这样使用反斜杠来转义路径分隔符：
pattern = Pattern.compile(
"^(.+?)\" +
File.separator +
"js\" +
File.separator +
"(.+?).js$" );
回答by gimel
Why don't you escape File.separator:
你为什么不逃跑File.separator：
... +
"\" + File.separator +
...
to fit Pattern.compilerequirements?
I hope "/" (unix case) is processed as a single "/".
满足Pattern.compile要求？我希望“/”（unix 大小写）作为单个“/”处理。
回答by Alnitak
I've tested gimel's answer on a Unix system - putting "\\" + File.separatorworks fine - the resulting "\/"in the pattern correctly matches a single "/"
我已经在 Unix 系统上测试了 gimel 的答案 - 放置"\\" + File.separator工作正常 - 导致"\/"模式正确匹配单个"/"
