Android：如何初始化“位置”类型的变量（除了使其等于 null）
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Android: How to initialize a variable of type "Location" (other than making it equal to null)
提问by Skizit
I'm looking to test some code I've written and to do so I need to construct a variable of type Location and to give it a long / lat value but I'm unsure how I would do so. Any ideas?
我希望测试我编写的一些代码，为此我需要构造一个 Location 类型的变量并为其赋予一个 long / lat 值，但我不确定我将如何这样做。有任何想法吗？
回答by Matti Virkkunen
The API documentationis quite clear on this. First create a new Location instance:
API 文档对此非常清楚。首先创建一个新的 Location 实例：
Location loc = new Location("dummyprovider");
And then use the setter methods to set the location parameters you need, e.g.:
然后使用setter方法设置你需要的位置参数，例如：
loc.setLatitude(20.3);
loc.setLongitude(52.6);
回答by Atta Ullah
Location object = new Location("service Provider");
it will create an object of Type Location that contains the initial Latitude and Longitude at location '0' to get the initial values use
它将创建一个 Location 类型的对象，其中包含位置 '0' 处的初始纬度和经度，以获取使用的初始值
double lat = object.getLatitude();
double lng = object.getLongitude();
回答by Kuvalya
You can write a method:
你可以写一个方法：
Location createNewLocation(double longitude, double latitude) {
Location location = new Location("dummyprovider");
location.setLongitude(longitude);
location.setLatitude(latitude);
return location;
}
And then call it:
然后调用它：
Location myLoc = createNewLocation(dLong, dLati);
Or you can use string with Double.parse():
或者您可以将字符串与 Double.parse() 一起使用：
Location myLoc = createNewLocation(Double.parse("s.Long"), Double.parse("s.Lati"));
回答by Shylendra Madda
In Kotlin using LocationManagerclass you can pass the required location provider like:
在 Kotlin 中使用LocationManager类，您可以传递所需的位置提供程序，例如：
val location = Location(LocationManager.NETWORK_PROVIDER) // OR GPS_PROVIDER based on the requirement
location.latitude = 42.125
location.longitude = 55.123
