javascript 正则表达式测试仅适用于 6 位数字。逗号分隔

javascript regular expression test for 6 digit numbers only. comma seperated

提问by Norman Bird

and so this must pass:

所以这必须通过：

454555, 939999 , 019999    ,727663

its for a user entering 6 digit invoice numbers. it should fail if a number is 5 or 7 digit and not 6. so 1234567, 123456should fail, as one set is more than 6 numbers.

它适用于输入 6 位发票编号的用户。如果数字是 5 或 7 位而不是 6，它1234567, 123456应该会失败。所以应该会失败，因为一组超过 6 个数字。

So far I have :

到目前为止我有：

[0-9]{6}(\s*,*,\s*[0-9]{6})*

which only draw back is that it accepts 7 or more digit numbers. cant figure out if its even possible at this point to do both, test for 6 digits separated by a comma and one or more space, and all the digits have to be only 6 digits and fail if one is not.

唯一的缺点是它接受 7 位或更多位数字。无法弄清楚此时是否可以同时执行这两项操作，测试由逗号和一个或多个空格分隔的 6 位数字，并且所有数字必须只有 6 位，如果不是，则失败。

any help appreciated. regular expressions are not my forte.

任何帮助表示赞赏。正则表达式不是我的强项。

thanks

谢谢

Norman

诺曼

采纳答案by Jesko R.

In order to validate the full string you can use this regex.

为了验证完整的字符串，您可以使用此正则表达式。

^(\s*\d{6}\s*)(,\s*\d{6}\s*)*,?\s*$

It works with six digits only, and you have to enter at least one 6 digit number. It also works if you have a trailing comma with whitespaces.

它仅适用于六位数字，您必须输入至少一个 6 位数字。如果您有一个带空格的尾随逗号，它也有效。

回答by Bariscode

You can write it using regex like the function below.

您可以像下面的函数一样使用正则表达式编写它。

const isPassword = (password: string) => /^\d{6}$/gm.test(password);

And here is an example test file below.

这是下面的示例测试文件。

  test('should recognize a valid password', () => {
    expect(isPassword('123456')).toBe(true);
    expect(isPassword('000000')).toBe(true);
  });

  test('should recognize an invalid password', () => {
    expect(isPassword('asdasda1234')).toBe(false);
    expect(isPassword('1234567')).toBe(false);
    expect(isPassword('a123456a')).toBe(false);
    expect(isPassword('11.11.11')).toBe(false);
    expect(isPassword('aaaaaa')).toBe(false);
    expect(isPassword('eeeeee')).toBe(false);
    expect(isPassword('......')).toBe(false);
    expect(isPassword('werwerwerwr')).toBe(false);
  });

回答by nickb

It's accepting more than six digit numbers because you're not anchoring the text, and for some odd reason you're optionally repeating the comma. Try something like this:

它接受超过六位数的数字，因为您没有锚定文本，并且出于某种奇怪的原因，您可以选择重复逗号。尝试这样的事情：

^[0-9]{6}(?:\s*,\s*[0-9]{6})*$

Also note that [0-9]is equivalent to \d, so this can be rewritten more concisely as:

另请注意，[0-9]等效于\d，因此可以更简洁地将其重写为：

^\d{6}(?:\s*,\s*\d{6})*$

回答by Paul

Your regex does not match 7digits in a row, but it also doesn't enforce that it matches the whole string. It just has to match some substring in the string, so it would also match each of these:

您的正则表达式不匹配7一行中的数字，但它也不强制它匹配整个字符串。它只需要匹配字符串中的一些子字符串，所以它也会匹配这些中的每一个：

"1234512345612345612345"
"NaNaNaN  123456,    123456 BOOO!"
"!@#$%^&*({123456})*&^%$#@!"

Just add the start of string (^) and end of string ($) anchors to enforce that the whole string matches and it will work correctly:

只需添加字符串的开头 ( ^) 和字符串的结尾 ( $) 锚点以强制整个字符串匹配，它就会正常工作：

^[0-9]{6}(\s*,*,\s*[0-9]{6})*$

Also note that ,*,could be shortened to ,+, and if you only want one comma in a row, just use ,, not ,*or ,+.

另请注意，,*,可以缩短为,+, 如果您只想要一行中的一个逗号，只需使用,, not ,*or ,+。

You can also replace [0-9]with \d:

您还可以替换[0-9]为\d：

^\d{6}(\s*,\s*\d{6})*$

回答by jeff

There isn;t any real need for a regexp. Limit the input to only 6 characters, only accept numbers and ensure that the input has 6 digits (not show here). So you would need:

没有任何真正需要正则表达式。将输入限制为仅 6 个字符，只接受数字并确保输入有 6 位数字（此处未显示）。所以你需要：

HTML

HTML

<input type='text' name='invoice' size='10' maxlength='6' value='' onkeypress='evNumersOnly(event);'>

JavaScript

JavaScript

<script>
function evNumbersOnly( evt ) {
  //---  only accepts numbers
  //--- this handles incompatabilities between browsers
  var theEvent = evt || window.event;
  //--- this handles incompatabilities between browsers
  var key = theEvent.keyCode || theEvent.which;
  //--- convert key number to a letter
  key = String.fromCharCode( key );
  var regex = /[0-9]/;      // Allowable characters 0-9.+-,
  if( !regex.test(key) ) {
    theEvent.returnValue = false;
    //--- this prevents the character from being displayed
    if(theEvent.preventDefault) theEvent.preventDefault();
  }
}
</script>

回答by Justin Morgan

I see a lot of complication here. Sounds to me like what you want is pretty simple:

我在这里看到了很多复杂性。听起来你想要的东西很简单：

/^(\d{6},)*\d{6}$/

Then we account for whitespace:

然后我们考虑空格：

/^\s*(\d{6}\s*,\s*)*\d{6}\s*$/

But as others have noted, this is actually quite simple in JavaScript without using regex:

但正如其他人所指出的，这在 JavaScript 中实际上非常简单，无需使用正则表达式：

function check(input) {
    var parts = input.split(',');
    for (var i = 0, n = parts.length; i < n; i++) {
        if (isNaN(+parts[i].trim())) {
            return false;
        }
    }
    return true;
}

Tested in the Chrome JavaScript console.

在 Chrome JavaScript 控制台中测试。

回答by Phrogz

Using only regex:

仅使用正则表达式：

var commaSeparatedSixDigits = /^(?:\d{6}\s*,\s*)*\d{6}$/;
if (myInput.test(commaSeparatedSixDigits)) console.log( "Is good!" );

This says:

这说：

• ^- Starting at the beginning of the string
• (?:…)*- Find zero or more of the following:
  • \d{6}- six digits
  • \s*- maybe some whitespace
  • ,- a literal comma
  • \s*- maybe some whitespace
• \d{6}- Followed by six digits
• $- Followed by the end of the string

• ^- 从字符串的开头开始
• (?:…)*- 找到以下零个或多个：
  • \d{6}- 六位数
  • \s*- 也许一些空白
  • ,- 字面逗号
  • \s*- 也许一些空白
• \d{6}- 后跟六位数
• $- 后跟字符串的结尾

Alternatively:

或者：

var commaSeparatedSixDigits = /^\s*\d{6}(?:\s*,\s*\d{6})*\s*$/;

I leave it as an exercise to you to decipher what's different about this.

我把它留给你作为一个练习来解读这其中的不同之处。

---

---

Using JavaScript + regex:

使用 JavaScript + 正则表达式：

function isOnlyCommaSeparatedSixDigitNumbers( str ){
  var parts = srt.split(/\s*,\s*/);
  for (var i=parts.length;i--;){
    // Ensure that each part is exactly six digit characters
    if (! /^\d{6}$/.test(parts[i])) return false;
  }
  return true;
}