java 获取一个类的所有（派生）接口
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get all (derived) interfaces of a class
提问by markdsievers
java.lang.Class.getInterfacesreturns all directly implemented interfaces ie doesn't walk the class tree to get all interfaces of all parent types. eg For example the hierarchy
java.lang.Class.getInterfaces返回所有直接实现的接口，即不遍历类树来获取所有父类型的所有接口。例如，例如层次结构
public interface A {}
public interface B {}
public interface C extends B {}
public class Foo implements A {} // Foo.class.getInterfaces() returns [A]
public class Bar implements C {} // Bar.class.getInterfaces() returns [C], note B is not included.
For BarI would like to get [B, C], but for any arbitrary tree depth.
因为Bar我想得到[B, C]，但是对于任意的树深度。
I could write this myself, but I'm sure a library must exist that does this already, any ideas?
我可以自己写这个，但我确定必须存在一个已经这样做的图书馆，有什么想法吗？
回答by Alex Gitelman
Apache Commons Langhas method you need: ClassUtils.getAllInterfaces
回答by markdsievers
Guava Solution:
番石榴解决方案：
final Set<TypeToken> tt = TypeToken.of(cls).getTypes().interfaces();
This is a much more powerful and cleaner reflection API than the ancient Apache stuff.
这是一个比古老的 Apache 东西更强大、更干净的反射 API。
回答by Igor Rybak
Don't forget, Spring Frameworkhas many similar util classes like Apache Commons Lang. So there is: org.springframework.util.ClassUtils#getAllInterfaces
别忘了，Spring Framework有很多类似的 util 类，比如 Apache Commons Lang。所以有：org.springframework.util.ClassUtils#getAllInterfaces
