jQuery:获取从 <input type="file" /> 中选择的文件名
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jQuery: get the file name selected from <input type="file" />
提问by Thinker
This code should work in IE(don't even test it in Firefox), but it doesn't. What I want is to display the name of the attached file. Any help?
这段代码应该在 IE 中工作(甚至不要在 Firefox 中测试它),但它没有。我想要的是显示附件的名称。有什么帮助吗?
<html>
<head>
<title>example</title>
<script type="text/javascript" src="../js/jquery.js"></script>
<script type="text/javascript">
$(document).ready( function(){
$("#attach").after("<input id='fakeAttach' type='button' value='attach a file' />");
$("#fakeAttach").click(function() {
$("#attach").click();
$("#maxSize").after("<div id='temporary'><span id='attachedFile'></span><input id='remove' type='button' value='remove' /></div>");
$('#attach').change(function(){
$("#fakeAttach").attr("disabled","disabled");
$("#attachedFile").html($(this).val());
});
$("#remove").click(function(e){
e.preventDefault();
$("#attach").replaceWith($("#attach").clone());
$("#fakeAttach").attr("disabled","");
$("#temporary").remove();
});
})
});
</script>
</head>
<body>
<input id="attach" type="file" /><span id="maxSize">(less than 1MB)</span>
</body>
</html>
回答by Thinker
It is just such simple as writing:
就是这么简单的写:
$('input[type=file]').val()
Anyway, I suggest using name or ID attribute to select your input. And with event, it should look like this:
无论如何,我建议使用 name 或 ID 属性来选择您的输入。对于事件,它应该是这样的:
$('input[type=file]').change(function(e){
$in=$(this);
$in.next().html($in.val());
});
回答by Anatolii Pazhyn
$('input[type=file]').change(function(e){
$(this).parents('.parent-selector').find('.element-to-paste-filename').text(e.target.files[0].name);
});
This code will not show C:\fakepath\
before file name in Google Chrome in case of using .val()
.
此代码将不会显示C:\fakepath\
在使用的情况下,之前在谷歌浏览器的文件名.val()
。
回答by James111
The simplest way is to simply use the following line of jquery
, using this you don't get the /fakepath
nonsense, you straight up get the file that was uploaded:
最简单的方法是简单地使用以下行jquery
,使用这个你不会得到/fakepath
废话,你直接得到上传的文件:
$('input[type=file]')[0].files[0]; // This gets the file
$('#idOfFileUpload')[0].files[0]; // This gets the file with the specified id
Some other useful commands are:
其他一些有用的命令是:
To get the name of the file:
要获取文件名:
$('input[type=file]')[0].files[0].name; // This gets the file name
To get the type of the file:
要获取文件的类型:
If I were to upload a PNG, it would return image/png
如果我要上传 PNG,它会返回 image/png
$("#imgUpload")[0].files[0].type
To get the size (in bytes) of the file:
要获取文件的大小(以字节为单位):
$("#imgUpload")[0].files[0].size
Also you don't have to use these commands on('change'
, you can get the values at any time, for instance you may have a file upload and when the user clicks upload
, you simply use the commands I listed.
此外,您不必使用这些命令on('change'
,您可以随时获取这些值,例如您可以上传文件,当用户单击时upload
,您只需使用我列出的命令。
回答by Anil Gupta
<input onchange="readURL(this);" type="file" name="userfile" />
<img src="" id="blah"/>
<script>
function readURL(input) {
if (input.files && input.files[0]) {
var reader = new FileReader();
reader.onload = function (e) {
$('#blah')
.attr('src', e.target.result)
.width(150).height(200);
};
reader.readAsDataURL(input.files[0]);
//console.log(reader);
//alert(reader.readAsDataURL(input.files[0]));
}
}
</script>
回答by ihmar
I had used following which worked correctly.
我使用了以下工作正常的方法。
$('#fileAttached').attr('value', $('#attachment').val())
回答by redsquare
//get file input
var $el = $('input[type=file]');
//set the next siblings (the span) text to the input value
$el.next().text( $el.val() );
回答by daniel ye
Add a hidden reset button :
添加隐藏的重置按钮:
<input id="Reset1" type="reset" value="reset" class="hidden" />
Click the reset button to clear the input.
单击重置按钮清除输入。
$("#Reset1").click();
回答by Raghuraj Singh Gurjar
<input onchange="readURL(this);" type="file" name="userfile" />
<img src="" id="viewImage"/>
<script>
function readURL(fileName) {
if (fileName.files && fileName.files[0]) {
var reader = new FileReader();
reader.onload = function (e) {
$('#viewImage')
.attr('src', e.target.result)
.width(150).height(200);
};
reader.readAsDataURL(fileName.files[0]);
}
}
</script>