C++ 如何判断头文件是从哪里包含的?
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How to tell where a header file is included from?
提问by harschware
How can I tell where g++ was able to find an include file? Basically if I
我如何知道 g++ 在哪里能够找到包含文件?基本上如果我
#include <foo.h>
g++ will scan the search path, using any include options to add or alter the path. But, at the end of days, is there a way I can tell the absolute path of foo.h that g++ chose to compile? Especially relevant if there is more than one foo.h in the myriad of search paths.
g++ 将扫描搜索路径,使用任何包含选项来添加或更改路径。但是,最终,有没有办法告诉我 g++ 选择编译的 foo.h 的绝对路径?如果在无数的搜索路径中存在多个 foo.h,则尤其重要。
Short of a way of accomplishing that... is there a way to get g++ to tell me what its final search path is after including defaults and all include options?
缺少实现这一点的方法......有没有办法让 g++ 告诉我在包含默认值和所有包含选项之后它的最终搜索路径是什么?
采纳答案by Sodved
This will give make dependencies which list absolute paths of include files:
这将提供 make 依赖项,其中列出了包含文件的绝对路径:
gcc -M showtime.c
If you don't want the system includes (i.e. #include <something.h>
) then use:
如果您不希望系统包含(即#include <something.h>
),请使用:
gcc -MM showtime.c
回答by Bulletmagnet
g++ -H ...
will also print the full path of include files in a format which shows which header includes which
还将以一种格式打印包含文件的完整路径,该格式显示哪个标题包含哪个
回答by wallyk
Sure use
肯定用
g++ -E -dI ... (whatever the original command arguments were)
回答by Jonathan Leffler
If you use -MM
or one of the related options (-M
, etc), you get just the list of headers that are included without having all the other preprocessor output (which you seem to get with the suggested g++ -E -dI
solution).
如果您使用-MM
或 相关选项之一(-M
等),您只会获得包含的标头列表,而没有所有其他预处理器输出(您似乎可以通过建议的g++ -E -dI
解决方案获得)。