如何将 PHP 对象转换为字符串？
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How to convert a PHP object to a string?
提问by Rohan
Possible Duplicate:
PHP ToString() equivalent
可能的重复：
PHP ToString() 等效
I get this error:
我收到此错误：
Catchable fatal error: Object of class stdClass could not be converted to string
So, my question is, how do I convert an object to a string in PHP? I don't want to serialize it though.
所以，我的问题是，如何在 PHP 中将对象转换为字符串？我不想序列化它。
Just a note: the code I use works in PHP 4, but not in PHP 5
请注意：我使用的代码适用于 PHP 4，但不适用于 PHP 5
Thanks!
谢谢！
EDIT: I resolved it myself. It was a pain, but I did it. Thanks anyway, everyone :-)
编辑：我自己解决了。这很痛苦，但我做到了。无论如何，谢谢大家:-)
回答by Wim
Why do you need this string? If you just need to visualize it for debugging, you can use var_dump(), print_r(), or $s = print_r($var, 1);to really make it into a string for further theming. If you need to send the object as text to somewhere else (database, Javascript code), you have a choice of serialize, json_encode, XML conversion, and many more, depending on your exact situation.
为什么需要这个字符串？如果您只是需要将其可视化以进行调试，您可以使用 var_dump()、print_r()，或者$s = print_r($var, 1);将其真正变成字符串以进行进一步的主题化。如果您需要将对象作为文本发送到其他地方（数据库、Javascript 代码），您可以选择序列化、json_encode、XML 转换等等，具体取决于您的具体情况。
回答by nickl-
You want to convert a PHP object to a string?
您想将 PHP 对象转换为字符串吗？
if neither var_dump, print_r, var_export, serialize, json_encodenor __toStringis exactly what you're after maybe this can help you satisfy your needs.
如果var_dump、print_r、var_export、serialize、json_encode和__toString都不是您想要的，那么这可能可以帮助您满足您的需求。
For PHP 5.3 and above
对于 PHP 5.3 及以上
<?php
$v = (object) array('a' => 1, 'b' => 2, 'c' => 3);
$r = new ReflectionObject($v);
echo $r->getName() .' {' . implode(', ', array_map(
function($p) use ($v) {
$p->setAccessible(true);
return $p->getName() .': '. $p->getValue($v);
}, $r->getProperties())) .'}';
Will output:
将输出：
stdClass {a: 1, b: 2, c: 3}
For a more conventional approach compatible with previous PHP 5 flavours try
对于与以前的 PHP 5 风格兼容的更传统的方法，请尝试
<?php
class ExampleClass {
private $pvt = 'private';
protected $prot = 'protected';
public $pub = 'public';
}
$v = new ExampleClass();
$r = new ReflectionObject($v);
echo $r->getName() ." {\n";
foreach ($r->getProperties() as $p)
if ($p->isPublic())
echo "\tpublic ".$p->getName().': '.$p->getValue($v)."\n";
else
echo "\t".($p->isPrivate()?'private ':'protected ').$p->getName().",\n";
echo "}\n";
Which will print:
这将打印：
ExampleClass {
protected pvt,
protected prot,
public pub: public
}
回答by p4bl0
What you need is to add the magic method __toStringto your class so you can print what you want.
您需要的是将魔术方法添加__toString到您的类中，以便您可以打印您想要的内容。
Edit: Sorry, just saw "PHP 4, but not in PHP 5".
编辑：抱歉，刚刚看到“PHP 4，但不是 PHP 5”。
回答by Gabriel Solomon
you can use php magic method __toString
您可以使用 php 魔术方法__toString
回答by K. Norbert
I suspect that this is not a problem with the object not convertable to a string.
我怀疑这不是不可转换为字符串的对象的问题。
It's more like that you are assuming that a variable contains a string, (or something that can represented as a string), but it contains an object, and you are trying to echo that out.
这更像是假设一个变量包含一个字符串（或可以表示为字符串的东西），但它包含一个对象，而您正试图将其回显出来。
回答by back2dos
from the error you get I assume you used the object as a parameter to a function that expects a string. the question is, why you did that and what you expect that function to with the object. and then before passing it to the function, extract a sensible string value.
从您得到的错误中，我假设您将该对象用作需要字符串的函数的参数。问题是，你为什么这样做以及你期望该函数对对象有什么作用。然后在将其传递给函数之前，提取一个合理的字符串值。
回答by MAS1
You do not try to convert this Object in string,it will not work. Just fetch exact value from that Object.
您不要尝试将此对象转换为字符串，它不会起作用。只需从该对象中获取精确值。
As a example if you got output as cost.this cost output is Object. so fetch exact value from this as follows
举个例子，如果你的输出是成本。这个成本输出是对象。所以从这里获取确切的值如下
$var=cost->Postage_cost;
$var1=cost->other_cost;
