Java Spring Security 和 CAS 集成
声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow
原文地址: http://stackoverflow.com/questions/9834710/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Spring Security and CAS Integration
提问by Rajesh
Can anyone paste simple steps to integrate Spring security and CAS over here for single sign on and single sign out.
Note I dont want any role based access.I have a web application which is already integrated with spring security. Now I was trying to perform SSO with CAS,but I am getting this error sun.security.provider.certpath.SunCertPathBuilderException: unable to find valid certification path to requested target
任何人都可以在此处粘贴简单的步骤来集成 Spring 安全性和 CAS 以进行单点登录和单点注销。注意我不想要任何基于角色的访问。我有一个已经与 Spring Security 集成的 Web 应用程序。现在我正在尝试使用 CAS 执行 SSO,但我收到此错误 sun.security.provider.certpath.SunCertPathBuilderException: unable to find valid certification path to requested target
This is my current spring security.xml
这是我当前的 spring security.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:sec="http://www.springframework.org/schema/security"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="
http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd
http://www.springframework.org/schema/jee http://www.springframework.org/schema/jee/spring-jee.xsd
http://www.springframework.org/schema/lang http://www.springframework.org/schema/lang/spring-lang.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx.xsd
http://www.springframework.org/schema/util http://www.springframework.org/schema/util/spring-util.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security-3.1.xsd
">
<sec:http entry-point-ref="casProcessingFilterEntryPoint" >
<sec:intercept-url pattern="/**" access="ROLE_USER" />
<sec:logout logout-success-url="/loggedout.jsp" invalidate-session="true"/>
<sec:custom-filter ref="casAuthenticationFilter" after="CAS_FILTER"/>
</sec:http>
<sec:authentication-manager alias="authenticationManager">
<sec:authentication-provider ref="casAuthenticationProvider"/>
</sec:authentication-manager>
<bean id="casAuthenticationFilter" class="org.springframework.security.cas.web.CasAuthenticationFilter">
<property name="authenticationManager" ref="authenticationManager"/>
<property name="authenticationFailureHandler">
<bean class="org.springframework.security.web.authentication.SimpleUrlAuthenticationFailureHandler">
<property name="defaultFailureUrl" value="/casfailed.jsp"/>
</bean>
</property>
<property name="authenticationSuccessHandler">
<bean class="org.springframework.security.web.authentication.SimpleUrlAuthenticationSuccessHandler">
<property name="defaultTargetUrl" value="/"/>
</bean>
</property>
</bean>
<bean id="casProcessingFilterEntryPoint" class="org.springframework.security.cas.web.CasAuthenticationEntryPoint">
<property name="loginUrl" value="https://cegicollabdev.india.xxx.com:8443/cas/login"/>
<property name="serviceProperties" ref="serviceProperties"/>
</bean>
<bean id="casAuthenticationProvider" class="org.springframework.security.cas.authentication.CasAuthenticationProvider">
<property name="userDetailsService" ref="userService"/>
<property name="serviceProperties" ref="serviceProperties" />
<property name="ticketValidator">
<bean class="org.jasig.cas.client.validation.Cas20ServiceTicketValidator">
<constructor-arg index="0" value="https://cegicollabdev.india.tcs.com:8443/cas" />
</bean>
</property>
<property name="key" value="an_id_for_this_auth_provider_only"/>
</bean>
<bean id="serviceProperties" class="org.springframework.security.cas.ServiceProperties">
<property name="service" value="http://localhost:8080/dbcomparision/j_spring_cas_security_check"/>
<property name="sendRenew" value="false"/>
</bean>
<bean id="userService" class="com.tcs.ceg.services.impl.UserServiceImpl" />
<!-- <sec:global-method-security pre-post-annotations="enabled" />
<sec:http pattern="/css/**" security="none"/>
<sec:http pattern="/images/**" security="none"/>
<sec:http pattern="/js/**" security="none"/>
<sec:http pattern="/index.jsp" security="none"/>
<sec:http pattern="/app/addNewUser.json" security="none"/>
<sec:http pattern="/dbcomplogin.jsp" security="none"/>
<sec:http pattern="/loggedout.jsp" security="none"/>
<sec:http use-expressions="true">-->
<!--
Allow all other requests. In a real application you should
adopt a whitelisting approach where access is not allowed by default
-->
<!-- <sec:intercept-url pattern="/**" access="isAuthenticated()" />
<sec:form-login login-page='/dbcomplogin.jsp'
authentication-failure-url="/dbcomplogin.jsp?login_error=1"
default-target-url="/index.jsp" />
<sec:logout logout-success-url="/loggedout.jsp" delete-cookies="JSESSIONID"/>
<sec:remember-me />
</sec:http>
<bean id="myUserService" class="com.tcs.ceg.services.impl.UserServiceImpl" />
<sec:authentication-manager>
<sec:authentication-provider user-service-ref="myUserService" />
</sec:authentication-manager> -->
</beans>
This is my web.xml
这是我的 web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
<display-name>Spring3MVC</display-name>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/spring-rootcontext.xml
/WEB-INF/spring-security.xml
</param-value>
</context-param>
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<!--
- Loads the root application context of this web app at startup.
-->
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>spring</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>spring</servlet-name>
<url-pattern>/app/*</url-pattern>
</servlet-mapping>
<filter>
<filter-name>CAS Single Sign Out Filter</filter-name>
<filter-class>org.jasig.cas.client.session.SingleSignOutFilter</filter-class>
</filter>
<filter-mapping>
<filter-name>CAS Single Sign Out Filter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<listener>
<listener-class>org.jasig.cas.client.session.SingleSignOutHttpSessionListener</listener-class>
</listener>
</web-app>
This is my Spring-rootcontext.xml
这是我的 Spring-rootcontext.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:jee="http://www.springframework.org/schema/jee"
xmlns:lang="http://www.springframework.org/schema/lang"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:util="http://www.springframework.org/schema/util"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd
http://www.springframework.org/schema/jee http://www.springframework.org/schema/jee/spring-jee.xsd
http://www.springframework.org/schema/lang http://www.springframework.org/schema/lang/spring-lang.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx.xsd
http://www.springframework.org/schema/util http://www.springframework.org/schema/util/spring-util.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd" >
<context:annotation-config />
<mvc:annotation-driven />
<context:component-scan
base-package="com.tcs.ceg" />
<jee:jndi-lookup id="dataSource1" jndi-name="jdbc/PmdDS"/>
<bean id="sessionFactory"
class="org.springframework.orm.hibernate3.LocalSessionFactoryBean">
<property name="dataSource" ref="dataSource1" />
<property name="configLocation">
<value>classpath:hibernate.cfg.xml</value>
</property>
<property name="configurationClass">
<value>org.hibernate.cfg.AnnotationConfiguration</value>
</property>
<property name="hibernateProperties">
<props>
<prop key="hibernate.dialect">org.hibernate.dialect.PostgreSQLDialect</prop>
<prop key="hibernate.show_sql">true</prop>
<prop key="current_session_context_class">thread</prop>
<prop key="cache.provider_class">org.hibernate.cache.NoCacheProvider</prop>
<prop key="hibernate.connection.release_mode">auto</prop>
</props>
</property>
</bean>
<tx:annotation-driven />
<bean id="transactionManager"
class="org.springframework.orm.hibernate3.HibernateTransactionManager">
<property name="sessionFactory" ref="sessionFactory" />
</bean>
</beans>
This is my spring-servlet.xml
这是我的 spring-servlet.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:jee="http://www.springframework.org/schema/jee"
xmlns:lang="http://www.springframework.org/schema/lang"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:util="http://www.springframework.org/schema/util"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd
http://www.springframework.org/schema/jee http://www.springframework.org/schema/jee/spring-jee.xsd
http://www.springframework.org/schema/lang http://www.springframework.org/schema/lang/spring-lang.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx.xsd
http://www.springframework.org/schema/util http://www.springframework.org/schema/util/spring-util.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd" >
<bean id="viewResolver"
class="org.springframework.web.servlet.view.UrlBasedViewResolver">
<property name="viewClass">
<value>
org.springframework.web.servlet.view.tiles2.TilesView
</value>
</property>
</bean>
<bean id="tilesConfigurer"
class="org.springframework.web.servlet.view.tiles2.TilesConfigurer">
<property name="definitions">
<list>
<value>/WEB-INF/tiles.xml</value>
</list>
</property>
</bean>
<bean id="messageSource"
class="org.springframework.context.support.ReloadableResourceBundleMessageSource">
<property name="basename" value="classpath:messages" />
<property name="defaultEncoding" value="UTF-8"/>
</bean>
<bean id="localeChangeInterceptor"
class="org.springframework.web.servlet.i18n.LocaleChangeInterceptor">
<property name="paramName" value="lang" />
</bean>
<bean id="localeResolver"
class="org.springframework.web.servlet.i18n.CookieLocaleResolver">
<property name="defaultLocale" value="en"/>
</bean>
<bean id="handlerMapping"
class="org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping">
<property name="interceptors">
<ref bean="localeChangeInterceptor" />
</property>
</bean>
<bean id="multipartResolver" class="org.springframework.web.multipart.commons.CommonsMultipartResolver">
<!-- one of the properties available; the maximum file size in bytes -->
<property name="maxUploadSize" value="1000000000000"/>
</bean>
</beans>
Problem : 1 sun.security.provider.certpath.SunCertPathBuilderException: unable to find valid certification path to requested target
问题:1 sun.security.provider.certpath.SunCertPathBuilderException: unable to find valid certification path to requested target
Problem 2: Custom UserServiceimpl is not getting called
问题 2:未调用自定义 UserServiceimpl
Problem 3: Is this correct ? <property name="service" value="http://localhost:8080/dbcomparision/j_spring_cas_security_check"/>
,Note In my program no Request Mapping is there for j_spring_cas_security_check
问题 3:这是正确的吗?<property name="service" value="http://localhost:8080/dbcomparision/j_spring_cas_security_check"/>
,注意在我的程序中没有 j_spring_cas_security_check 的请求映射
采纳答案by Shaun the Sheep
The simplest steps to getting CAS authentication working is to build and run the CAS samplefrom the Spring Security source tree.
使 CAS 身份验证工作的最简单步骤是从 Spring Security 源代码树构建和运行CAS 示例。
You really need to understand how CAS works before you try to use it, or integrate it with your application. I would start on the CAS documentation and the Spring Security reference manual which describes the interactions between CAS and Spring Security.
在尝试使用 CAS 或将其与应用程序集成之前,您确实需要了解 CAS 的工作原理。我将从 CAS 文档和描述CAS 和 Spring Security 之间交互的 Spring Security 参考手册开始。
j_spring_cas_security_check
is the URL which the CAS redirects to in your application after it has authenticated the user (see the above link).
j_spring_cas_security_check
是 CAS 在对用户进行身份验证后重定向到您的应用程序中的 URL(请参阅上面的链接)。
Even if your application isn't authenticating users, it still typically has a concept of users it knows about. It also has to load the roles for these users, which CAS doesn't handle, hence the user-service
declaration. The password won't be used.
即使您的应用程序没有对用户进行身份验证,它通常仍然具有它所知道的用户概念。它还必须为这些用户加载角色,CAS 不处理这些角色,因此需要user-service
声明。密码不会被使用。
How your application validates that a login is successful is explained in documentation above. It basically calls the CAS server, passing in the service ticket and gets back a response with the username.
上面的文档解释了您的应用程序如何验证登录是否成功。它基本上调用 CAS 服务器,传入服务票证并返回带有用户名的响应。
回答by Rajesh
Anyway single sign on is done..It took lot of time to figureout but trust me if you have a mind setup that you want to do it then anyway u will succeed ..here is the solution.. Here is my updated spring-security.xml
无论如何,单点登录完成了..花了很多时间来弄清楚但相信我,如果你有一个想要这样做的想法,那么无论如何你都会成功..这是解决方案..这是我更新的spring-security .xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:sec="http://www.springframework.org/schema/security"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="
http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd
http://www.springframework.org/schema/jee http://www.springframework.org/schema/jee/spring-jee.xsd
http://www.springframework.org/schema/lang http://www.springframework.org/schema/lang/spring-lang.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx.xsd
http://www.springframework.org/schema/util http://www.springframework.org/schema/util/spring-util.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security-3.1.xsd
">
<sec:http entry-point-ref="casProcessingFilterEntryPoint" >
<sec:intercept-url pattern="/**" access="ROLE_ADMIN" />
<sec:logout logout-success-url="https://abc.com:8443/cas/logout" delete-cookies="JSESSIONID"/>
<sec:custom-filter ref="requestSingleLogoutFilter" before="LOGOUT_FILTER"/>
<sec:custom-filter ref="singleLogoutFilter" before="CAS_FILTER"/>
<sec:custom-filter ref="casAuthenticationFilter" after="CAS_FILTER"/>
</sec:http>
<sec:authentication-manager alias="authenticationManager">
<sec:authentication-provider ref="casAuthenticationProvider"/>
</sec:authentication-manager>
<bean id="casAuthenticationFilter" class="org.springframework.security.cas.web.CasAuthenticationFilter">
<property name="authenticationManager" ref="authenticationManager"/>
<property name="authenticationFailureHandler">
<bean class="org.springframework.security.web.authentication.SimpleUrlAuthenticationFailureHandler">
<property name="defaultFailureUrl" value="/casfailed.jsp"/>
</bean>
</property>
<property name="authenticationSuccessHandler">
<bean class="org.springframework.security.web.authentication.SimpleUrlAuthenticationSuccessHandler">
<property name="defaultTargetUrl" value="/"/>
</bean>
</property>
<property name="proxyGrantingTicketStorage" ref="proxyGrantingTicketStorage" />
<property name="proxyReceptorUrl" value="/secure/receptor" />
</bean>
<bean id="casProcessingFilterEntryPoint" class="org.springframework.security.cas.web.CasAuthenticationEntryPoint">
<property name="loginUrl" value="https://abc.com:8443/cas/login"/>
<property name="serviceProperties" ref="serviceProperties"/>
</bean>
<bean id="casAuthenticationProvider" class="org.springframework.security.cas.authentication.CasAuthenticationProvider">
<property name="userDetailsService" ref="userService"/>
<property name="serviceProperties" ref="serviceProperties" />
<property name="ticketValidator">
<bean class="org.jasig.cas.client.validation.Cas20ServiceTicketValidator">
<constructor-arg index="0" value="https://abc.com:8443/cas" />
<property name="proxyGrantingTicketStorage" ref="proxyGrantingTicketStorage" />
<property name="proxyCallbackUrl" value="http://localhost:8080/dbcomparision/secure/receptor" />
</bean>
</property>
<property name="key" value="an_id_for_this_auth_provider_only"/>
</bean>
<bean id="proxyGrantingTicketStorage" class="org.jasig.cas.client.proxy.ProxyGrantingTicketStorageImpl" />
<bean id="serviceProperties" class="org.springframework.security.cas.ServiceProperties">
<property name="service" value="http://localhost:8080/dbcomparision/j_spring_cas_security_check"/>
<property name="sendRenew" value="false"/>
</bean>
<bean id="userService" class="com.tcs.ceg.services.impl.UserServiceImpl" />
<!-- This filter handles a Single Logout Request from the CAS Server -->
<bean id="singleLogoutFilter" class="org.jasig.cas.client.session.SingleSignOutFilter"/>
<!-- This filter redirects to the CAS Server to signal Single Logout should be performed -->
<bean id="requestSingleLogoutFilter"
class="org.springframework.security.web.authentication.logout.LogoutFilter">
<constructor-arg value="https://abc.com:8443/cas/logout"/>
<constructor-arg>
<bean class=
"org.springframework.security.web.authentication.logout.SecurityContextLogoutHandler"/>
</constructor-arg>
<property name="filterProcessesUrl" value="/j_spring_cas_security_logout"/>
</bean>
</beans>
my updated web.xml
我更新的 web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
<display-name>Spring3MVC</display-name>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/spring-rootcontext.xml
/WEB-INF/spring-security.xml
</param-value>
</context-param>
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<!--
- Loads the root application context of this web app at startup.
-->
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>spring</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>spring</servlet-name>
<url-pattern>/app/*</url-pattern>
</servlet-mapping>
<filter>
<filter-name>CAS Single Sign Out Filter</filter-name>
<filter-class>org.jasig.cas.client.session.SingleSignOutFilter</filter-class>
</filter>
<filter-mapping>
<filter-name>CAS Single Sign Out Filter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<listener>
<listener-class>org.jasig.cas.client.session.SingleSignOutHttpSessionListener</listener-class>
</listener>
</web-app>
I resolved this exception javax.net.ssl.SSLHandshakeException: sun.security.validator.ValidatorException: PKIX path building failed: sun.security.provider.certpath.SunCertPathBuilderException: unable to find valid certification path to requested target at com.sun.net.ssl.internal.ssl.Alerts.getSSLException(Unknown Source)
by copying CAS server "cacerts" file from java\jre\lib\security of CAS server to my local java\jre\lib\security and exception was smoked.
我javax.net.ssl.SSLHandshakeException: sun.security.validator.ValidatorException: PKIX path building failed: sun.security.provider.certpath.SunCertPathBuilderException: unable to find valid certification path to requested target at com.sun.net.ssl.internal.ssl.Alerts.getSSLException(Unknown Source)
通过将 CAS 服务器的“cacerts”文件从 CAS 服务器的 java\jre\lib\security 复制到我的本地 java\jre\lib\security解决了这个异常,并且异常被抽了。
回答by bnguyen82
To solve the problem
解决问题
sun.security.provider.certpath.SunCertPathBuilderException: unable to find valid certification path to requested target
sun.security.provider.certpath.SunCertPathBuilderException:无法找到请求目标的有效认证路径
We follow 3 steps to instruct JDK of our app server accept cas server's certificate (in your project, it's cegicollabdev.india.tcs.com:8443)
我们按照 3 个步骤来指示我们应用服务器的 JDK 接受 cas 服务器的证书(在您的项目中,它是 cegicollabdev.india.tcs.com:8443)
Download InstallCert.java, and copy to JDK'bin folder
http://code.google.com/p/java-use-examples/source/browse/trunk/src/com/aw/ad/util/InstallCert.java
Open command line tool with Administrator privilege (if you're on Window 7/Vista). Change to JDK's bin folder and build this java file
javac InstallCert.java
Install cas server certificate
java InstallCert cegicollabdev.india.tcs.com:8443
Hit 1 when prompted.
下载InstallCert.java,复制到JDK'bin文件夹
http://code.google.com/p/java-use-examples/source/browse/trunk/src/com/aw/ad/util/InstallCert.java
以管理员权限打开命令行工具(如果您使用的是 Window 7/Vista)。切换到JDK的bin文件夹,构建这个java文件
javac InstallCert.java
安装cas服务器证书
java InstallCert cegicollabdev.india.tcs.com:8443
出现提示时按 1。
That's all.
就这样。