PHP 星期几数字到星期几文本
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PHP day of week numeric to day of week text
提问by csi
This may be really easy but I can't find a PHP function to do this...
这可能真的很简单，但我找不到 PHP 函数来执行此操作...
OK so
好吧
$dow_numeric = date('w');
gives the numeric day of the week 0-6 for Sunday to Saturday.
给出星期日到星期六的星期数 0-6。
And
和
$dow_text = date('D');
gives the 3 letter abbreviation for the text day of the week (Sun, Mon, etc.)
给出一周中文本日期的 3 个字母缩写（Sun、Mon 等）
Is there a function or easy way to use $dow_numericto get $dow_text? If I have '0' as $dow_numeric, how can I make $dow_text = 'Sun'? Yes a switchstatement could do the job, but I'm looking for a more elegant solution.
有没有函数或简单的方法可以$dow_numeric用来获取$dow_text？如果我有 '0' as $dow_numeric，我该怎么做$dow_text = 'Sun'？是的，switch声明可以完成这项工作，但我正在寻找更优雅的解决方案。
采纳答案by ThiefMaster
Create an array to map numeric DOWs to text DOWs.
创建一个数组以将数字 DOW 映射到文本 DOW。
$dowMap = array('Sun', 'Mon', 'Tue', 'Wed', 'Thu', 'Fri', 'Sat');
If you need locale support, load the dow of some random date (epoch (0) would be a good date for example) and then for the next 6 days and build the dow map dynamically.
如果您需要语言环境支持，请加载某个随机日期的 dow（例如，epoch (0) 将是一个很好的日期），然后在接下来的 6 天内动态构建 dow 地图。
回答by Hamish
Bit of a hack, but:
有点黑客，但是：
$dow_text = date('D', strtotime("Sunday +{$dow_numeric} days"));
回答by Chibueze Opata
It's not popular, but there's actually a function jddayofweekfor this in PHP. You can call it with the second parameter as 1 to get full gregorian week day name or 2 for the abbreviated name.
它并不流行，但实际上jddayofweek在 PHP 中有一个函数。您可以使用第二个参数作为 1 来调用它以获得完整的公历星期名称或 2 作为缩写名称。
e.g. jddayofweek(2, 2); #returns Wed
Note that for this function, numbers start at Monday. So Monday=0, Tuesday=1, ...
请注意，对于此函数，数字从星期一开始。所以星期一=0，星期二=1，...
回答by Reza Mamun
To get Sunday to Saturdayfrom numeric day of the week 0 to 6:
要从星期0 到 6 的数字日期获得星期日到星期六：
//For example, our target numeric day is 0 (Sunday):
$numericDay = 0; //assuming current date('w')==0 and date('D')=='Sun';
Solution-1:Using PHP's built-in function jddayofweek()which starts from Mondaywhereas date('w')starts from Sunday:
解决方法1：使用PHP的内置函数 jddayofweek（）从开始Monday，而date('w')从开始Sunday：
jddayofweek($numericDay-1, 1); //returns 'Sun', here decreasing by '-1' is important(!)
//jddayofweek(0, 1); //returns 'Mon';
//jddayofweek(0, 2); //returns 'Monday';
Solution-2:Using a trick(!):
解决方案 2：使用技巧（！）：
date('D', strtotime("Sunday +{$numericDay} days")); //returns 'Sun';
//date('l', strtotime("Sunday +{$numericDay} days")); //returns 'Sunday';
回答by Azaz Khan
function getDay(){
$dowMap = array('Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday');
$dow_numeric = date('w');
return $dowMap[$dow_numeric];
}
回答by CodeBrauer
If you need locale support you can use a bit improved function of Hamishs answer:
如果您需要语言环境支持，您可以使用Hamishs 答案的一些改进功能：
Example using german weekdays:
使用德国工作日的示例：
setlocale(LC_TIME, 'de_DE');
$dow_numeric = 3;
$dow_text = strftime('%A', strtotime("Sunday +{$dow_numeric} days"));
If $dow_numericstart on 0(0= Monday) you can just change Sundayto Mondayor
add $dow_numeric += 1
如果$dow_numeric从0（0= 星期一）开始，您可以更改Sunday为Monday或添加$dow_numeric += 1
回答by Matt Lowden
This should work:
这应该有效：
$dow_numeric = 3;
$last_sunday = strtotime('last Sunday');
$dow_text = date('D', strtotime('+'.$dow_numeric.' day', $last_sunday));
