用于验证 URL 的 Jquery 验证
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/16537628/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Jquery Validation to validate URL
提问by Roopendra
I am trying to validate URL in jQuery regular expressionusing below code. It is working fine with http://wwwand https://www
我正在尝试regular expression使用以下代码验证 jQuery 中的 URL 。它与http://www和https://www
var myVariable = "http://www.example.com/2013/05/test-page-url-512-518.html";
if(/^(http:\/\/www\.|https:\/\/www\.|http:\/\/|https:\/\/|www\.)[a-z0-9]+([\-\.]{1}[a-z0-9]+)*\.[a-z]{2,5}(:[0-9]{1,5})?(\/.*)?$/.test(myVariable)){
alert("valid url");
} else {
alert("invalid url");
}
Edit:-
编辑：-
Above code work perfectly to validate URL. That time my requirement was only to validate http://wwwand https://www
上面的代码可以完美地验证 URL。那个时候我的要求只是验证http://www和https://www
采纳答案by Chu Ya'an Xiaonan
your pattern is defined as
你的模式被定义为
^(http:\/\/|someting elsethus any-urls begin with "http://" would be validated.
因此任何以“http://”开头的网址都将被验证。
回答by ChamingaD
Check this - http://docs.jquery.com/Plugins/Validation/Methods/url
检查这个 - http://docs.jquery.com/Plugins/Validation/Methods/url
$("#myform").validate({
rules: {
field: {
required: true,
url: true
}
}
});
回答by Santosh Panda
You can change your Regex, actually there is a repetition of item i.e. http:\/\/|https:\/\/|www\.
你可以改变你的正则表达式，实际上有一个项目的重复，即 http:\/\/|https:\/\/|www\.
This code will work out for you:
此代码将为您解决：
var myVariable = "http://www.example.com/2013/05/test-page-url-512-518.html";
if(/^(http:\/\/www\.|https:\/\/www\.)[a-z0-9]+([\-\.]{1}[a-z0-9]+)*\.[a-z]{2,5}(:[0-9]{1,5})?(\/.*)?$/.test(myVariable)){
alert("valid url");
} else {
alert("invalid url");
}
回答by Vishnu Sharma
You want to validate your URL:
您想验证您的网址：
Please pass the URL in this function then this will give you true OR false.
请在此函数中传递 URL，然后这将为您提供 true 或 false。
The Function :
功能 ：
<script>
function isUrl(s) {
var regexp = /(ftp|http|https):\/\/(\w+:{0,1}\w*@)?(\S+)(:[0-9]+)?(\/|\/([\w#!:.?+=&%@!\-\/]))?/
return regexp.test(s);
}
isUrl(yourURL);
</script>
回答by Ashok Damani
try this--->
试试这个--->
var myVariable = "http://www.Test.com/";
if(/^([a-z]([a-z]|\d|\+|-|\.)*):(\/\/(((([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(%[\da-f]{2})|[!$&'\(\)\*\+,;=]|:)*@)?((\[(|(v[\da-f]{1,}\.(([a-z]|\d|-|\.|_|~)|[!$&'\(\)\*\+,;=]|:)+))\])|((\d|[1-9]\d|1\d\d|2[0-4]\d|25[0-5])\.(\d|[1-9]\d|1\d\d|2[0-4]\d|25[0-5])\.(\d|[1-9]\d|1\d\d|2[0-4]\d|25[0-5])\.(\d|[1-9]\d|1\d\d|2[0-4]\d|25[0-5]))|(([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(%[\da-f]{2})|[!$&'\(\)\*\+,;=])*)(:\d*)?)(\/(([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(%[\da-f]{2})|[!$&'\(\)\*\+,;=]|:|@)*)*|(\/((([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(%[\da-f]{2})|[!$&'\(\)\*\+,;=]|:|@)+(\/(([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(%[\da-f]{2})|[!$&'\(\)\*\+,;=]|:|@)*)*)?)|((([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(%[\da-f]{2})|[!$&'\(\)\*\+,;=]|:|@)+(\/(([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(%[\da-f]{2})|[!$&'\(\)\*\+,;=]|:|@)*)*)|((([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(%[\da-f]{2})|[!$&'\(\)\*\+,;=]|:|@)){0})(\?((([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(%[\da-f]{2})|[!$&'\(\)\*\+,;=]|:|@)|[\uE000-\uF8FF]|\/|\?)*)?(\#((([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(%[\da-f]{2})|[!$&'\(\)\*\+,;=]|:|@)|\/|\?)*)?$/i.test(myVariable)) {
alert("valid url");
} else {
alert("invalid url");
}
