从 Python 列表项中删除标点符号
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Removing Punctuation From Python List Items
提问by giodamelio
I have a list like
我有一个像
['hello', '...', 'h3.a', 'ds4,']
this should turn into
这应该变成
['hello', 'h3a', 'ds4']
and i want to remove only the punctuation leaving the letters and numbers intact.
Punctuation is anything in the string.punctuationconstant.
I know that this is gunna be simple but im kinda noobie at python so...
我只想删除标点符号，而保留字母和数字。标点符号是string.punctuation常数中的任何东西。我知道这很简单，但我在 python 方面有点菜鸟，所以......
Thanks, giodamelio
谢谢，乔达梅利奥
采纳答案by Mark Byers
Assuming that your initial list is stored in a variable x, you can use this:
假设您的初始列表存储在变量 x 中，您可以使用：
>>> x = [''.join(c for c in s if c not in string.punctuation) for s in x]
>>> print(x)
['hello', '', 'h3a', 'ds4']
To remove the empty strings:
要删除空字符串：
>>> x = [s for s in x if s]
>>> print(x)
['hello', 'h3a', 'ds4']
回答by Rafe Kettler
To make a new list:
要创建新列表：
[re.sub(r'[^A-Za-z0-9]+', '', x) for x in list_of_strings]
回答by Ant
import string
print ''.join((x for x in st if x not in string.punctuation))
ps st is the string. for the list is the same...
ps st 是字符串。因为名单是一样的......
[''.join(x for x in par if x not in string.punctuation) for par in alist]
i think works well. look at string.punctuaction:
我认为效果很好。看看 string.punctuaction：
>>> print string.punctuation
!"#$%&\'()*+,-./:;<=>?@[\]^_`{|}~
回答by Josh Bleecher Snyder
Use string.translate:
使用 string.translate：
>>> import string
>>> test_case = ['hello', '...', 'h3.a', 'ds4,']
>>> [s.translate(None, string.punctuation) for s in test_case]
['hello', '', 'h3a', 'ds4']
For the documentation of translate, see http://docs.python.org/library/string.html
有关翻译的文档，请参阅http://docs.python.org/library/string.html
回答by florex
In python 3+ use this instead:
在 python 3+ 中改用这个：
import string
s = s.translate(str.maketrans('','',string.punctuation))
