java 如何删除特定标记之前的所有内容，包括字符串中的标记
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How to remove everything that comes before a particular token, including the token from a String
提问by Nigel Thomas
Possible Duplicate:
Remove a particular token from a string
可能的重复：
从字符串中删除特定标记
This question is a continuation to my earlier question
这个问题是我之前问题的延续
I need to remove whatever that comes before the "+" and the "+" from the String.
我需要从字符串中删除“+”和“+”之前的任何内容。
How can it be done?
怎么做到呢？
回答by PermGenError
Use String#substring()and String#indexOfin combination
使用字符串＃子（）和字符串的indexOf＃结合
String s= "GUID+456709876790";
System.out.println(s.substring(s.indexOf("+")+1));
Output: 456709876790
输出：456709876790
回答by Jaco Van Niekerk
If the String is in the format +text+, a regular expression may do the trick:
如果字符串的格式为 +text+，正则表达式可能会起作用：
Pattern p = Pattern.compile(".*\+(.*)\+.*");
Matcher m = p.matcher("sdasdad+982347347+234234234");
if (m.matches()) {
System.out.println("Here you go: " + m.group(1));
}
The entire recognised string is group 0, the content in the first bracket is group 1.
整个识别出的字符串为0组，第一个括号中的内容为1组。
