从 URL 创建一个 JavaScript 数组

Make a JavaScript array from URL

提问by skazhy

I need to make a Javascript array from URL, eg:

我需要从 URL 创建一个 Javascript 数组，例如：

turn this:

转这个：

http://maps.google.com/maps/api/staticmap?center=Baker Street 221b, London&size=450x450&markers=Baker Street 221b, London&sensor=false

Into something like:

进入类似的东西：

array['center'] = Baker Street 221b, London
array['size'] = 450x450
// and so on...

I need to make this serializaion/unserialization work both ways (url to array and array to the part of the url). Are there some built-in functions that do this?

我需要使这个序列化/反序列化双向工作（url 到数组和数组到 url 的一部分）。是否有一些内置函数可以做到这一点？

Thanks in advance!

提前致谢！

回答by casablanca

URL to array: (adapted from my answer here)

数组的 URL：（根据我的回答改编）

function URLToArray(url) {
    var request = {};
    var pairs = url.substring(url.indexOf('?') + 1).split('&');
    for (var i = 0; i < pairs.length; i++) {
        if(!pairs[i])
            continue;
        var pair = pairs[i].split('=');
        request[decodeURIComponent(pair[0])] = decodeURIComponent(pair[1]);
     }
     return request;
}

Array to URL:

数组到 URL：

function ArrayToURL(array) {
  var pairs = [];
  for (var key in array)
    if (array.hasOwnProperty(key))

      pairs.push(encodeURIComponent(key) + '=' + encodeURIComponent(array[key]));
  return pairs.join('&');
}

回答by alex toader

the above function URLToArray is not working when url string has elem[]=23&elem[]=56.. see below the adapted function... hope it is working - not 100% tested

当 url 字符串具有 elem[]=23&elem[]=56 时，上面的函数 URLToArray 不起作用..见下面的适应函数......希望它起作用 - 不是 100% 测试

function URLToArray(url) {
        var request = {};
        var arr = [];
        var pairs = url.substring(url.indexOf('?') + 1).split('&');
        for (var i = 0; i < pairs.length; i++) {
          var pair = pairs[i].split('=');

          //check we have an array here - add array numeric indexes so the key elem[] is not identical.
          if(endsWith(decodeURIComponent(pair[0]), '[]') ) {
              var arrName = decodeURIComponent(pair[0]).substring(0, decodeURIComponent(pair[0]).length - 2);
              if(!(arrName in arr)) {
                  arr.push(arrName);
                  arr[arrName] = [];
              }

              arr[arrName].push(decodeURIComponent(pair[1]));
              request[arrName] = arr[arrName];
          } else {
            request[decodeURIComponent(pair[0])] = decodeURIComponent(pair[1]);
          }
        }
        return request;
    }

where endWith is taken from here

endWith 取自此处

function endsWith(str, suffix) {
    return str.indexOf(suffix, str.length - suffix.length) !== -1;
}

回答by SEN

 /**
 * (C)VIOLONIX inc.
 * Parser for make multidim array from
 * foo[]=any&foo[]=boy, or foo[0][kids]=any&foo[1][kids]=boy
 * result: foo=[[any],[boy]] or foo=[kids:[any],kids:[boy]]
 */    

 var URLToArray = function(url){
        function parse_mdim(name, val, data){
            let params = name.match(/(\[\])|(\[.+?\])/g);
            if(!params)params = new Array();
            let tg_id = name.split('[')[0];


            if(!(tg_id in data)) data[tg_id] = [];
            var prev_data = data[tg_id];

            for(var i=0;i<params.length;i++){
                if(params[i]!='[]'){
                    let tparam = params[i].match(/\[(.+)\]/i)[1];
                    if(!(tparam in prev_data)) prev_data[tparam] = [];
                    prev_data = prev_data[tparam];
                }else{
                    prev_data.push([]);
                    prev_data = prev_data[prev_data.length-1];
                }

            }
            prev_data.push(val);

        }


        var request = {};
        var arr = [];
        var pairs = url.substring(url.indexOf('?') + 1).split('&');

        for (var i = 0; i < pairs.length; i++) {
           var pair = pairs[i].split('=');
           if(decodeURIComponent(pair[0]).indexOf('[')!=-1)
               parse_mdim(decodeURIComponent(pair[0]), decodeURIComponent(pair[1]), request);
           else 
               request[decodeURIComponent(pair[0])] = decodeURIComponent(pair[1]);
         }

        //To-do here check array and simplifity it: if parameter end with one index in array replace it by value [0]    

         return request;

    }

回答by Eric

There's the query-objectjQuery pluginfor that

还有的query-objectjQuery插件为