Mac 上 C++ 中的分段错误 11
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segmentation fault 11 in C++ on Mac
提问by mariusz2108
When I try to run this
当我尝试运行它时
int N=10000000;
short res[N];
I get segmentation fault 11
我得到分段错误 11
when I change to
当我改为
int N=1000000;
short res[N];
it works fine
它工作正常
回答by Bartek Banachewicz
You've exceeded your stack space given by the OS. If you need more memory, the easiest way is to allocate it dynamically:
您已超出操作系统提供的堆栈空间。如果需要更多内存，最简单的方法是动态分配：
int N=1000000;
short* res = new short[N];
However, std::vectoris preferred in this context, because the above requires you to freethe memory by hand.
但是，std::vector在这种情况下是首选，因为上面需要您free手动进行记忆。
int N = 1000000;
std::vector<short> res (N);
If you can use C++11, you can possibly save some fraction of time by using unique_ptrarray specialization, too:
如果你可以使用 C++11，你也可以通过使用unique_ptr数组特化来节省一些时间：
std::unique_ptr<short[]> res (new short[N]);
Both of the automatic methods above can still be used with familiar res[index]syntax thanks to overloaded operator[], but to get the raw pointer for memory operations you'd need res.data()with vectoror res.get()with unique_ptr.
上述两种自动方法仍然可以使用熟悉的使用res[index]语法由于超载operator[]，但要得到你需要的内存操作的原始指针res.data()与vector或res.get()有unique_ptr。
回答by IdeaHat
You can't allocate all that on the stack. Try short* res = new short[10000000];and don't forget to clean up.
您不能在堆栈上分配所有这些。尝试short* res = new short[10000000];并且不要忘记清理。
Alternatively, you can use std::vector<short> res(10000000);
或者，您可以使用std::vector<short> res(10000000);
