Java 正则表达式：如何知道字符串至少包含 2 个大写字母？
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Regex: how to know that string contains at least 2 upper case letters?
提问by Ernestas Gruodis
How to know that string contains at least 2 upper case letters? For example these are valid strings "Lazy Cat", "NOt very lazy cat". Working with Java 1.7.
如何知道字符串至少包含 2 个大写字母？例如，这些是有效的字符串“Lazy Cat”、“NOt very lazy cat”。使用 Java 1.7。
采纳答案by hsz
Try with following regex:
尝试使用以下正则表达式：
"^(.*?[A-Z]){2,}.*$"
or
或者
"^(.*?[A-Z]){2,}"
回答by Pratik Tari
Try this:
尝试这个：
string.matches("[A-Z]+.*[A-Z]+");
回答by Jules G.M.
This regex works.
这个正则表达式有效。
string.matches(".*[A-Z].*[A-Z].*")
回答by Maroun
I'll now show you a full solution, I'll guide you.
我现在将向您展示一个完整的解决方案，我会指导您。
If you don't want to use regex, you can simply loop on the String, chat by char and check whether it's an upper case:
如果你不想使用正则表达式，你可以简单地循环字符串，按字符聊天并检查它是否是大写：
for (int i=0;i<myStr.length();i++)
{
//as @sanbhat suggested, use Character#isUpperCase on each character..
}
回答by Suresh Atta
You have somany regex answers right now,
你现在有很多正则表达式的答案，
Go for it if you don't want to use **regex**,
如果你不想使用**regex**，就去吧，
String someString = "abcDS";
int upperCount = 0;
for (char c : someString.toCharArray()) {
if (Character.isUpperCase(c)) {
upperFound++;
}
}
// upperFound here weather >2 or not
