bash Sed：获取以一些前缀开头的行
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时间：2020-09-09 22:54:34 来源:igfitidea点击:
Sed: get lines beginning with some prefix
提问by CAMOBAP
I have file Blackberry jad file:
我有文件 Blackberry jad 文件：
RIM-COD-URL-12: HelloWorld-12.cod
RIM-COD-Size: 68020
RIM-MIDlet-Icon-2-1: ____HOVER_ICON_res/icon/blackberry/icon-68.png,focused
RIM-COD-URL-11: HelloWorld-11.cod
RIM-MIDlet-Icon-Count-2: 1
RIM-COD-URL-10: HelloWorld-10.cod
RIM-MIDlet-Icon-Count-1: 1
MIDlet-Vendor: Vasia Pupkin
RIM-MIDlet-Icon-1-1: res\icon\blackberry\____HOVER_ICON_icon-68.png,focused
Manifest-Version: 1.0
RIM-MIDlet-Flags-1: 0
RIM-COD-SHA1-38: 9a c8 b3 35 72 de 34 5e 7a 0a 5b 9e c3 3a 65 4c 20 0f 8e 50
I just want to get lines begin with RIM-COD-.
我只想让行以RIM-COD-.
Can you provide me solutions for awkor sed?
你能为我提供了解决方案，awk或sed？
回答by John3136
Use sed -nand only print lines that match RIM-COD.
使用sed -n且仅打印与 RIM-COD 匹配的行。
sed -n -e '/^RIM-COD-/p' yourfile.txt
回答by Gilles Quenot
Try doing this :
尝试这样做：
awk '/^RIM-COD/' file.txt
Or
或者
grep "^RIM-COD" file.txt
Or
或者
sed -n '/^RIM-COD/p' file.txt
