从 bash 脚本检测“Windows 上的 Ubuntu”与本机 Ubuntu
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Detect "Ubuntu on Windows" vs native Ubuntu from bash script
提问by Tim
Can a bash script detect if it's running in "Ubuntu on Windows" vs native Ubuntu? If so, how?
bash 脚本是否可以检测它是在“Windows 上的 Ubuntu”还是本机 Ubuntu 中运行？如果是这样，如何？
I ran envon both machines and didn't see any obvious environmental variable differences. I could test for the existence of the /mnt/cdirectory, but that is not foolproof because that directory could potentially also be present on native Ubuntu.
我env在两台机器上运行，并没有看到任何明显的环境变量差异。我可以测试该/mnt/c目录是否存在，但这并不是万无一失的，因为该目录也可能存在于本机 Ubuntu 上。
回答by Tim
It looks like /proc/versionin Ubuntu on Windows contains:
/proc/version在 Windows 上的 Ubuntu 中看起来包含：
Linux version 3.4.0-Microsoft ([email protected]) (gcc version 4.7 (GCC) ) #1 SMP PREEMPT Wed Dec 31 14:42:53 PST 2014
Linux version 3.4.0-Microsoft ([email protected]) (gcc version 4.7 (GCC) ) #1 SMP PREEMPT Wed Dec 31 14:42:53 PST 2014
and my version of Ubuntu has:
我的 Ubuntu 版本有：
Linux version 4.4.0-31-generic (buildd@lgw01-16) (gcc version 5.3.1 20160413 (Ubuntu 5.3.1-14ubuntu2.1) ) #50-Ubuntu SMP Wed Jul 13 00:07:12 UTC 2016
Linux version 4.4.0-31-generic (buildd@lgw01-16) (gcc version 5.3.1 20160413 (Ubuntu 5.3.1-14ubuntu2.1) ) #50-Ubuntu SMP Wed Jul 13 00:07:12 UTC 2016
This code is working for me to detect which version of Ubuntu the script is running on:
这段代码让我可以检测脚本在哪个版本的 Ubuntu 上运行：
if grep -q Microsoft /proc/version; then
echo "Ubuntu on Windows"
else
echo "native Linux"
fi
