使用 Hibernate API 的 Java 字符串日期验证
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Java String Date Validation Using Hibernate API
提问by deadend
I am attempting to validate String Dateusing javax.validation& Hibernate validation. i need to check given String date should be past and it should be correct yyyyMMddformat with all constraints like leap year, 30th, 31stday.
我正在尝试 使用& Hibernate 验证来验证字符串日期javax.validation。我需要检查给定的字符串日期应该是过去的，并且它应该是正确的yyyyMMdd格式，并且具有所有约束，例如闰年30th、31st日。
public class UserInformation {
@NotNull
public String idNum = null;
@NotNull
//@Past
@Pattern(regexp="\d{4}(1[012]|0[1-9])(3[01]|[12]\d|0[0-9])")
public String dob= null;
}
I tried with this code but not working. Is there any solution. if we have custom validator then is it in field level.Please give suggestion or code snippet.
我尝试使用此代码但不起作用。有什么解决办法。如果我们有自定义验证器，那么它是否在字段级别。请给出建议或代码片段。
回答by Rafael Teles
Option 1
选项1
Change your pattern to this:
将您的模式更改为：
Pattern(regexp = "([0-2][0-9]|3[0-1])\/(0[1-9]|1[0-2])\/[0-9]{4}")
But keep in mind that this kind of validation is not checking if February has less than 28/29 days, and other dates constraints.
但请记住，这种验证不会检查二月是否少于 28/29 天，以及其他日期限制。
Options 2
选项 2
Create your custom constraint validator
创建您的自定义约束验证器
Annotation
注解
@Target({ElementType.FIELD, ElementType.METHOD, ElementType.PARAMETER, ElementType.ANNOTATION_TYPE })
@Retention(RUNTIME)
@Constraint(validatedBy = CheckDateValidator.class)
@Documented
public @interface CheckDateFormat {
String message() default "{message.key}";
Class<?>[] groups() default { };
Class<? extends Payload>[] payload() default { };
String pattern();
}
Validator class
验证器类
Having the Date object you can do any other validation you want (like refuse dates in the past)
拥有 Date 对象，您可以进行任何其他您想要的验证（例如拒绝过去的日期）
public class CheckDateValidator implements ConstraintValidator<CheckDateFormat, String> {
private String pattern;
@Override
public void initialize(CheckDateFormat constraintAnnotation) {
this.pattern = constraintAnnotation.pattern();
}
@Override
public boolean isValid(String object, ConstraintValidatorContext constraintContext) {
if ( object == null ) {
return true;
}
try {
Date date = new SimpleDateFormat(pattern).parse(object);
return true;
} catch (Exception e) {
e.printStackTrace();
return false;
}
}
}
Use
利用
@CheckDateFormat(pattern = "ddMMyyyy")
private String value;
回答by shazin
If you use Spring-Context Module as dependency you can use @DateTimeFormatand do the following.
如果您使用 Spring-Context Module 作为依赖项，您可以使用@DateTimeFormat并执行以下操作。
@NotNull
@DateTimeFormat(pattern="yyyyMMdd")
public String dob= null;
Or else you can write your own Custom Validator.
或者，您可以编写自己的自定义验证器。
