java 针对 xsd 执行 xml 验证
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/5351842/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
提示：将鼠标放在中文语句上可以显示对应的英文。显示中英文
时间：2020-10-30 10:44:38 来源:igfitidea点击:
performing xml validation against xsd
提问by volcano
I have XML as a string and an XSD as a file, and I need to validate the XML with the XSD. How can I do this?
我将 XML 作为字符串，将 XSD 作为文件，我需要使用 XSD 验证 XML。我怎样才能做到这一点？
回答by Steve Bennett
You can use javax.xml.validation API to do this.
您可以使用 javax.xml.validation API 来执行此操作。
public boolean validate(String inputXml, String schemaLocation)
throws SAXException, IOException {
// build the schema
SchemaFactory factory = SchemaFactory.newInstance("http://www.w3.org/2001/XMLSchema");
File schemaFile = new File(schemaLocation);
Schema schema = factory.newSchema(schemaFile);
Validator validator = schema.newValidator();
// create a source from a string
Source source = new StreamSource(new StringReader(inputXml));
// check input
boolean isValid = true;
try {
validator.validate(source);
}
catch (SAXException e) {
System.err.println("Not valid");
isValid = false;
}
return isValid;
}
回答by bdoughan
You can use the javax.xml.validationAPIs for this:
您可以为此使用javax.xml.validationAPI：
String xml = "<root/>"; // XML as String
File xsd = new File("schema.xsd"); // XSD as File
SchemaFactory sf = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
Schema schema = sf.newSchema(xsd);
SAXParserFactory spf = SAXParserFactory.newInstance();
spf.setSchema(schema);
SAXParser sp = spf.newSAXParser();
XMLReader xr = sp.getXMLReader();
xr.parse(new InputSource(new StringReader(xml)));
